All categories

1 year ago

A popular car has an engine that is reported to have a

Mathematics

1 answer:

Elis [28]1 year ago

5 0

The size of the car engine in cubic inches is 263.6 2 cubic inches

<h3>How to determine the size of the car engine in cubic inches?</h3>

The given parameters are

Volume = 4320 cubic centimeters

By general conversion rule, we have

1 cubic centimeter = 0.0610237 cubic inches

Multiply both sides of 1 cubic centimeter = 0.0610237 cubic inches by 4320

4320 * 1 cubic centimeter = 0.0610237 cubic inches * 4320

Evaluate the product

4320 cubic centimeters = 263.6 2cubic inches

Substitute 4320 cubic centimeters = 263.6 2cubic inches in Volume = 4320 cubic centimeters

Volume = 263.6 2cubic inches

Hence, the size of the car engine in cubic inches is 263.6 2cubic inches

You might be interested in

Y=x+ 5 <br>y = 6<br>HELP!!<br>Solve this system of equation algerbraically.

kati45 [8]

Answer:

x = 1

Step-by-step explanation:

plug y = 6 on to the equation y =x + 5

=> 6 = x +5

=> x = 1

5 0

3 years ago

Read 2 more answers

(7x2+3x-6)-(-4x2+x-2)

Alex17521 [72]

The correct answer is 4 ( 6x - 1 )

7 0

3 years ago

Read 2 more answers

OMG CAN SOMEONE PLEASE ANSWER MY QUESTIONSS LIKE THIS IS SO IMPORTANT AND YALL REALLY DONT CARE CAN YALL PLEASE GO TO MY THING A

Aleks04 [339]

You didn’t put the math problems for us to answer the questions

4 0

2 years ago

What is the surface area using integrals of these two lines. Y=10-x^2 and Y=x^2+2 from the bounds x=2 and x=-2.

Lelu [443]

Check the picture below.

$\bf \displaystyle\int\limits_{-2}^{2}~[\stackrel{\textit{above function}}{(10-x^2)}~~-~~\stackrel{\textit{below function}}{(x^2+2)}]dx\implies \int\limits_{-2}^{2}~(10-x^2-x^2-2)dx \\\\\\ \displaystyle\int\limits_{-2}^{2}~(8-2x^2)dx\implies \left. 8x\cfrac{}{} \right]_{-2}^{2}-\left. \cfrac{2x^3}{3} \right]_{-2}^{2} \\\\\\ ([16]-[-16])~~-~~\left( \left[ \cfrac{16}{3} \right]-\left[ -\cfrac{16}{3} \right]\right)\implies (32)~~-~~\left( \cfrac{32}{3} \right) \\\\\\ \cfrac{64}{3}\implies 21\frac{1}{3}$

5 0

3 years ago

An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (An ordinary (fair) coin is tossed 3 times. Ou)

shepuryov [24]

Answer:

Probability distribution

X P(X)

0 1/8

1 3/8

2 3/8

3 1/8

Step-by-step explanation:

When a coin is tossed there are two outcomes head and tail. When three coins are tossed the possible outcomes are

Sample space=S={HTH,THH,TTH,HHH,HTT,THT,TTT,HHT}

The total number of outcomes is n(S)=8. The X be the random variable counting number of tails in each outcome and so X can take values as 0,1,2,3. The probabilities can be computed as P(X)=n(X)/n(S). The probabilities are calculated as under:

X Outcomes P(X)

0 HHH 1/8

1 HHT,THH,HTH 3/8

2 TTH,HTT,THT 3/8

3 TTT 1/8

The probability distribution of X is as under:

X P(X)

0 1/8

1 3/8

2 3/8

3 1/8

4 0

3 years ago