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hichkok12 [17]
1 year ago
14

A popular car has an engine that is reported to have a

Mathematics
1 answer:
Elis [28]1 year ago
5 0

The size of the car engine in cubic inches is 263.6 2 cubic inches

<h3>How to determine the size of the car engine in cubic inches?</h3>

The given parameters are

Volume = 4320 cubic centimeters

By general conversion rule, we have

1 cubic centimeter = 0.0610237 cubic inches

Multiply both sides of 1 cubic centimeter = 0.0610237 cubic inches by 4320

4320 * 1 cubic centimeter = 0.0610237 cubic inches * 4320

Evaluate the product

4320 cubic centimeters = 263.6 2cubic inches

Substitute 4320 cubic centimeters = 263.6 2cubic inches  in Volume = 4320 cubic centimeters

Volume = 263.6 2cubic inches

Hence, the size of the car engine in cubic inches is 263.6 2cubic inches

Read more about volume at:

brainly.com/question/1972490

#SPJ1

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Answer:

x = 1

Step-by-step explanation:

plug y = 6 on to the equation y =x + 5

=> 6 = x +5

=> x = 1

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What is the surface area using integrals of these two lines. Y=10-x^2 and Y=x^2+2 from the bounds x=2 and x=-2.
Lelu [443]

Check the picture below.

\bf \displaystyle\int\limits_{-2}^{2}~[\stackrel{\textit{above function}}{(10-x^2)}~~-~~\stackrel{\textit{below function}}{(x^2+2)}]dx\implies \int\limits_{-2}^{2}~(10-x^2-x^2-2)dx \\\\\\ \displaystyle\int\limits_{-2}^{2}~(8-2x^2)dx\implies \left. 8x\cfrac{}{} \right]_{-2}^{2}-\left. \cfrac{2x^3}{3} \right]_{-2}^{2} \\\\\\ ([16]-[-16])~~-~~\left( \left[ \cfrac{16}{3} \right]-\left[ -\cfrac{16}{3} \right]\right)\implies (32)~~-~~\left( \cfrac{32}{3} \right) \\\\\\ \cfrac{64}{3}\implies 21\frac{1}{3}

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3 years ago
An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (An ordinary (fair) coin is tossed 3 times. Ou)
shepuryov [24]

Answer:

Probability distribution

X    P(X)

0    1/8

1     3/8  

2    3/8

3     1/8

Step-by-step explanation:

When a coin is tossed there are two outcomes head and tail. When three coins are tossed the possible outcomes are

Sample space=S={HTH,THH,TTH,HHH,HTT,THT,TTT,HHT}

The total number of outcomes is n(S)=8. The X be the random variable counting number of tails in each outcome and so X can take values as 0,1,2,3. The probabilities can be computed as P(X)=n(X)/n(S). The probabilities are calculated as under:

X   Outcomes           P(X)

0    HHH                    1/8

1     HHT,THH,HTH    3/8  

2    TTH,HTT,THT     3/8

3    TTT                        1/8

The probability distribution of X is as under:

X    P(X)

0    1/8

1     3/8  

2    3/8

3     1/8

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