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2 years ago

A popular car has an engine that is reported to have a

Mathematics

1 answer:

Elis [28]2 years ago

5 0

The size of the car engine in cubic inches is 263.6 2 cubic inches

<h3>How to determine the size of the car engine in cubic inches?</h3>

The given parameters are

Volume = 4320 cubic centimeters

By general conversion rule, we have

1 cubic centimeter = 0.0610237 cubic inches

Multiply both sides of 1 cubic centimeter = 0.0610237 cubic inches by 4320

4320 * 1 cubic centimeter = 0.0610237 cubic inches * 4320

Evaluate the product

4320 cubic centimeters = 263.6 2cubic inches

Substitute 4320 cubic centimeters = 263.6 2cubic inches in Volume = 4320 cubic centimeters

Volume = 263.6 2cubic inches

Hence, the size of the car engine in cubic inches is 263.6 2cubic inches

You might be interested in

The rules which tell which caculations are done before others in an expression

julia-pushkina [17]

This rule is known as PEMDAS

In an algebraic equation follow PEMDAS

P= first calculate anything with parantheses

E= then calculate anything with exponents

M= calculate any multiplication

D= calculate any division

A= calculate any addition

S= calculate any subtraction

you must do these in that order

hope this helps:)

5 0

3 years ago

One method of slowing the growth of an insect population without using pesticides is to introduce into the population a number o

Zielflug [23.3K]

To be clear, the given relation between time and female population is an integral:
 $t = \int { \frac{P+S}{P[(r - 1)P - S]} } \,
dP$

The problem says that r = 1.2 and S = 400, therefore substituting:
 $t = \int { \frac{P+400}{P[(1.2 - 1)P - 400]}
} \, dP$ 

= $
\int { \frac{P+400}{P(0.2P - 400)} } \, dP$

In order to evaluate this integral, we need to write this rational function in a simpler way:
 $\frac{P+400}{P(0.2P - 400)} = \frac{A}{P} +
\frac{B}{(0.2P - 400)}$ 

where we need to evaluate A and B. In order to do so, let's calculate the LCD:
 $\frac{P+400}{P(0.2P - 400)} = \frac{A(0.2P -
400)}{P(0.2P - 400)} + \frac{BP}{P(0.2P - 400)}$ 

the denominators cancel out and we get:
P + 400 = 0.2AP - 400A + BP
 = P(0.2A + B) - 400A

The two sides must be equal to each other, bringing the system:
 $\left \{ {{0.2A + B = 1} \atop {-400A =
400}} \right.$ 

Which can be easily solved:
 $\left \{ {{B=1.2} \atop {A=-1}} \right.$ 

Therefore, our integral can be written as:
 $t = \int { \frac{P+400}{P(0.2P - 400)} } \,
dP = \int {( \frac{-1}{P} + \frac{1.2}{0.2P-400} )} \, dP$ 
= $- \int { \frac{1}{P} \, dP +
1.2\int { \frac{1}{0.2P-400} } \, dP$ 
= $- \int { \frac{1}{P} \, dP +
6\int { \frac{0.2}{0.2P-400} } \, dP$ 
= - ln |P| + 6 ln |0.2P - 400| + C

Now, let’s evaluate C by considering that at t = 0 P = 10000:
0 = - ln |10000| + 6 ln |0.2(10000) - 400| + C
C = ln |10000| - 6 ln |1600|
C = ln (10⁴) - 6 ln (2⁶·5²)
C = 4 ln (10) - 36 ln (2) - 12 ln (5) 
 Therefore, the equation relating female population with time requested is:
t = - ln |P| + 6 ln |0.2P - 400| + 4 ln (10) - 36 ln (2) - 12 ln (5)

8 0

3 years ago

The quadratic function h(t)=-16.1t^2+150 models a balls height in feet over time in seconds after it is dropped from a 15 story

Allushta [10]

someone please answer

3 0

4 years ago

Here is a picture of a circle. Each square represents 1 square unit.

attashe74 [19]

We could go into calculating the area of the circle using the information we have, but I think this question just wants us to eyeball it.

Does each quadrant of the circle look like it's taking up more than half, or less than half of each square?

Probably looks like more doesn't it.

Which means that there's at least more than 2 square units being taken up by this square.

It also means that it's taking up less than 4 square units, since each square is not being filled up.

Is it more or less than 3?

It's really depends on the perspective on whoever looks at it, but to me personally, it looks like it's more than 3 units long.

Hope this helps.

頑張って!

5 0

3 years ago

Isabella is making a display board for the school council elections. the display is 4.25ft by 6 ft rectangle. she needs to add a

inna [77]

(4.25×2)+(6×2)=
8.5+12=20.5ft

5 0

3 years ago