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lubasha [3.4K]
3 years ago
5

Need help plz !

Mathematics
1 answer:
Phoenix [80]3 years ago
5 0
The vertical line is 5
The horizontal is 8
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A 4-pound bag of sugar contains 454 one-teaspoon servings and costs $3.49. A batch of muffins uses 1/4 cup of sugar. How many ba
Mazyrski [523]
48/4 = 12 teaspoons per each batch

454/12 = 37.83 batches can be made

3.49/37.83 = 0.092$ per each batch
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I need to rewrite d and h without the use of fractional or negative exponents by using radicals, how I do that???
jolli1 [7]

Answer:

The pencil marks on your page show you exactly how to do that.

Step-by-step explanation:

Take advantage of two rules of exponents:

\sqrt[n]{x}=x^{\frac{1}{n}}\\\\x^{-n}=\dfrac{1}{x^{n}}

(d)\quad x^{\frac{-1}{5}}=\dfrac{1}{x^{\frac{1}{5}}}=\dfrac{1}{\sqrt[5]{x}}\\\\(h)\quad x^{\frac{-2}{11}}=\dfrac{1}{x^{\frac{2}{11}}}=\dfrac{1}{\sqrt[11]{x^{2}}}

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Solve for y: 11−9y=−6y+8
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3 years ago
-8-6(1+7a)=32+4a
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3 0
3 years ago
Evidencia de aprendizaje Se desea obtener 80 kilogramos de café molido mezclando café arábico de S/18 el kilogramo y café torrad
SIZIF [17.4K]

Answer:

50kg de café torrado

30kg de café arábico

Step-by-step explanation:

Queremos obtener un total de 80kg de café molido.

Se utilizarán:

Café arábico, que cuesta $18 el kg

Café torrado, que cuesta $10 el kg

Queremos que el precio, por kilo, de la mezcla de 80kg sea $13.

Ok, primero debemos definir las variables:

Definamos:

x = cantidad de café arábico usado

y = cantidad de café torrado usado.

Entonces, como la mezcla deberá tener 80kg en total, tenemos:

x + y = 80kg

Y el costo total de esta mezcla será:

x*$18 + y*$10

Si lo dividimos por el peso total, tendremos el costo por kilo, que es:

(x*$18 + y*$10)/80kg

Y queremos que esto sea igual a $13, entonces tenemos la ecuación

(x*$18 + y*$10)/80kg = $13

Ok, ahora tenemos dos ecuaciones, es decir, tenemos un sistema de ecuaciones:

x + y = 80kg

(x*$18 + y*$10) = $13*80kg

(donde reescribimos levemente la segunda ecuación)

Ok, para resolver este sistema trataremos de reemplazar variables, para ello, el primer paso es aislar una de las variables en una de las ecuaciones.

Aislemos x en la primera:

x = 80kg - y

Ahora reemplazamos esto en la otra ecuación:

(x*$18 + y*$10) = $13*80kg

(( 80kg - y)*$18 + y*$10) = $13*80kg

Ahora podemos resolver esto para la variable y:

$18*80kg - $18*y + $10*y = $13*80kg

$18*80kg - $13*80kg = $18*y - $10*y

($18 - $13)*80kg = ($18 - $10)*y

$5*80kg = $8*y

($5*80kg)/$8 = y

50kg = y

Se usan 50kg de café torrado.

y como:

x + y = 80kg

x = 80kg - y

x = 80kg - 50kg = 30kg

Entonces los 30kg restantes serán de café arábico.

y la estrategia utilizada fue el remplazo de variables.

6 0
3 years ago
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