since the fence will be 3 sides, the length would be length minus 2 widths
so length = 1200 - 2x
area = length x width
width is x
area = (1200-2x)*x
= 1200x -2x^2
after doing the calculations x = 600 meters, width = 300 meters
You can write the dimensions of the rectangle as (x + 2) and (x - 5), and because the area is base × height, you can multiply the brackets together and make it equal to 56:
(x + 2)(2x - 5) = 56
2x² + 4x - 5x - 10 = 56
x² - x - 10 = 56
Now because you have an x², you need to make the equation equal to 0 so you can factorise, so:
2x² - x - 10 = 56
- 56
2x² - x - 66 = 0
(x - 6)(2x + 11)
So x is 6, because the other option is -5.5 and you cannot have a negative length.
I hope this helps!
2x - 2y + z = 5....multiply by -1
2x - 2y + 3z = 7
-------------------
-2x + 2y - z = -5 (result of multiplying by -1)
2x - 2y + 3z = 7
-------------------add
2z = 2
z = 2/2 = 1
2x - 2y + z = 5.....multiply by 3
-3x - 3y + 3z = 9...multiply by 2
-------------------
6x - 6y + 3z = 15 (result of multiplying by 3)
-6x - 6y + 6z = 18 (result of multiplying by 2)
-------------------add
-12y + 9z = 33
-12y + 9(1) = 33
-12y + 9 = 33
-12y = 33 - 9
-12y = 24
y = -24/12
y = -2
2x - 2y + z = 5
2x - 2(-2) + 1 = 5
2x + 4 + 1 = 5
2x + 5 = 5
2x = 5 - 5
2x = 0
x = 0
solution is : (0,-2,1)
Answer:
The width is 14ft
Step-by-step explanation:
Given
Required
Determine the width
To do this, we assume that the fence is a rectangle
So, we use the following formula.
Where:
So, we have:
Divide both sides by 2
Solve for Width
Because you start with $0.05, you're going to add that to whatever 0.01 is equal to after the amount of months
the equation I got was: v=0.05+(0.01m)
