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3 years ago

Need help plz !

Mathematics

1 answer:

Phoenix [80]3 years ago

5 0

The vertical line is 5
The horizontal is 8

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Work out the area of this trapezium

skelet666 [1.2K]

Step-by-step explanation:

Area = ½ × b × h

= ½ × (7.9 + 10.8) × 6.2

= ½ × 18.7 × 6.2

= ½ × 115.94

= 57.97 cm²

So, the area of that trapezium is 57.97 cm²

Hope it helpful and useful :)

6 0

2 years ago

The area of rectangular field is (49m2-42m+9).Find the dimensions of the field

Drupady [299]

Answer:

The dimensions are (7m-3) by (7m-3)

Step-by-step explanation:

We have the area of the rectangular field to be:

$49 {m}^{2} - 42m + 9$

We need to factorize this expression.

Let us rewrite to obtain:

${(7m)}^{2} - 2(7 \times 3)m + {3}^{2}$

We can easily see that the expression is actually a perfect square trinomial.

This gives us:

$(7m - 3)^{2}$

$(7m - 3)(7m - 3)$

6 0

3 years ago

HELP! What is AB? WILL GIVE BRAINLIEST!

Natalija [7]

AB = BC

3x-4=5x-10
-4=2x-10
6=2x
3=x

AB = 3x-4
AB = 3 (3)-4
AB = 9-4
AB =5

Therefore, AB is 5.

BC = 5x-10
BC = 5(3)-10
BC = 15-10
BC= 5

3 0

3 years ago

In a certain Algebra 2 class of 28 students, 11 of them play basketball and 13 of them play baseball. There are 11 students who

mina [271]

80 + 28 - 13 = 95 + 11 = 106

3 0

3 years ago

A projectile is launched from the ground at an angle of theta above the horizontal with an initial speed of v in ft/s. The rang

VARVARA [1.3K]

Answer:

$\theta=24.4^\circ$

Step-by-step explanation:

The formula you wrote has the fraction the other way around. You can find that the range of a projectile is in reality approximated by the equation $x=\frac{v^2}{g} sin(2\theta)=\frac{v^2}{32ft/s^2} sin(2\theta)$ , where we will use ft for distances.

From the given equation we have then $\frac{x32ft/s^2}{v^2} =sin(2\theta)$ , which means $\theta=\frac{Arcsin(\frac{x32ft/s^2}{v^2})}{2}$ since the arcsin is the inverse function of the sin.

Since we have x = 170 ft and v = 85 ft/s, we can substitute these values from the equation written, and we will have $\theta=\frac{Arcsin(\frac{(170ft)(32ft/s^2)}{(85ft/s)^2})}{2}$ , and from now on we have just to use a calculator, obtaining $\theta=\frac{Arcsin(0.75294117647)}{2}=\frac{48.84579804^\circ}{2}=24.4^\circ$

3 0

3 years ago