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lubasha [3.4K]
3 years ago
5

Need help plz !

Mathematics
1 answer:
Phoenix [80]3 years ago
5 0
The vertical line is 5
The horizontal is 8
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A rectangle is reduced by a scale factor of One-fourth.
Dvinal [7]

The ratio of the area of the smaller rectangle to the area of the larger rectangle is 1:16

Area of a rectangle

The formula for calculating the area of a rectangle is expressed as:

A = length * width

For the large triangle

Area = 16 * 12

Area of large triangle = 192 square units

For the smaller rectangle

Area = 4 * 3

Area. of small rectangle = 12 square units

Ratio = 12/192 = 1:16

Hence the ratio of the area of the smaller rectangle to the area of the larger rectangle is 1:16

Learn more on area of rectangle here: brainly.com/question/25292087

#SPJ1

6 0
2 years ago
HELP ME PLEASE!!!! I NEED THE ANSWER ASAP
Elza [17]
Yes
2828.
One says 28 is less than x and the other say x is more than 28.
It's just written in a different order is all.
7 0
4 years ago
WILL GIVE BRAINLIEST!!! The two larger segments below are perpendicular. Find the area of the shaded region to the nearest integ
snow_lady [41]

Answer:

I wont be able to help much and get you till all the way to the end but here is what i know:

Step-by-step explanation:

The radius of the smaller circle is 6, and the longer segment adds up to 12 since 6 + 6 = 12. the area of the whole bigger circle would be 452.389, by using the formula of the area of a circle "πr²". This is what i can tell and the only part I'm confused in how to find the area of JUST the shaded part. I hope this helped a bit!

5 0
3 years ago
What is the solution to the system of equations below?
sattari [20]

Answer:

<h2>x = 9, y = -36 → (9, -36)</h2>

Step-by-step explanation:

y=-3x-9\qquad(1)\\\\y=\dfrac{1}{3}x-39\qquad(2)\\\\\text{Substitute (1) to (2)}\\\\-3x-9=\dfrac{1}{3}x-39\qquad\text{multiply both sides by 3}\\\\-9x-27=x-117\qquad\text{add 27 to both sides}\\\\-9x=x-90\qquad\text{subtract}\ x\ \text{from both sides}\\\\-10x=-90\qquad\text{divide both sides by (-10)}\\\\x=9

\text{Put the value of x to (1):}\\\\y=-3(9)-9\\\\y=-27-9\\\\y=-36

7 0
3 years ago
30 points to who answers this first and will get brainliest answer
Aleonysh [2.5K]
Quadrant 2 is your answer because that is where J lies 
5 0
4 years ago
Read 2 more answers
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