This is a compound interest problem, therefore s(t) should be in the form:

where:
t = time in years
s(t) = the value of your item after t years
a = the initial value of your item
r = rate
Therefore, we already know that a = 245$.
Now, we can calculate r:

![r = \sqrt[t]{ \frac{s}{a} }](https://tex.z-dn.net/?f=r%20%3D%20%20%5Csqrt%5Bt%5D%7B%20%5Cfrac%7Bs%7D%7Ba%7D%20%7D%20)
![r = \sqrt[5]{ \frac{560.50}{245} }](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B5%5D%7B%20%5Cfrac%7B560.50%7D%7B245%7D%20%7D%20)
= 1.18
Therefore, the correct answers are
a = 245 and
r = 1.18
8 goes with 3/5: 10 goes with n (n being the number of cups)

Use cross products and we get 8n = 6
Now divide by 8
<u>8n</u> = <u>6
</u><u />8 8
n= 6/8 or 3/4 of a cup of flour.
Answer:
The average value of
over the interval
is
.
Step-by-step explanation:
Let suppose that function
is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of
over the interval
by algebraic handling:
![F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)](https://tex.z-dn.net/?f=F%285%29%20-%20F%283%29%20%2B%5BF%283%29-F%28-2%29%5D%20%3D%2040%20%2B%20%28-30%29)



The average value of
over the interval
is
.
Answer:
<h2>d = 8</h2><h2>g = 2</h2>
Step-by-step explanation:
8d + 4 = 5d + 28
Group like terms
That's
8d - 5d = 28 - 4
3d = 24
Divide both sides by 3
d = 8

Cross multiply
we have
7(7g + 8) = 38.5(4)
49g + 56 = 154
49g = 154 - 56
49g = 98
Divide both sides by 49
g = 2
Hope this helps you