What is the common denominator of 1/a + 1/b in the complex fraction 1/a - 1/b over 1/a+1/b?

Mathematics

1 answer:

9966 [12]2 years ago

4 0

Answer:

For this case we have the following fraction:

To find the common denominator, what we must do is rewrite the fraction.

For this, we subtract fractions in the numerator and the sum of fractions in the denominator.

We have then:

We observe that the common denominator is given by the product:

Answer:

the common denominator is:

D)ab

Step-by-step explanation:

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Why is it called numerator and denominator?

Airida [17]

Answer:

the numerator shows the top number of a fraction

the denominator shows you the bottom number of a fraction

Step-by-step explanation:

4 0

3 years ago

A. He refused to testify by invoking his Fifth Amendment rights, so he must be guilty. a. Identify the premise and conclusion o

mixer [17]

Answer:

a) C.

b) B.

Step-by-step explanation:

Remember that the premise is a statement that will led to a conclusion and justifies it.

a) In the sentence "He refused to testify by invoking his Fifth Amendment rights, so he must be guilty" the premise is: "He refused to testify by invoking his Fifth Amendment rights" because it follows from this that, therefore, he must be guilty (by not testifying, the person who said this reaches the conclusion that he must be guilty).

Thus, the correct answer is C.

b) Briefly describe how the stated fallacy occurs in the argument.

In this argument, the conclusion leaves no place for another outcome (because the conclusion is that he MUST be guilty), therefore it is stated as if being guilty is the only possible conclusion.

Thus, the correct answer is B.

6 0

3 years ago

The population of a certain species of bird in a region after t years can be modeled by the function P(t)= 1620/1+1.15e^-0.042t

natka813 [3]

Answer:

Step-by-step explanation:

The function is $\frac{1620}{1+1.15e^{-0.042t}}$

To find the maximum population, we need to set t towards infinity to get our answer.

So, we replace time with maximum ( $\infty$ ). Let's check:

$\frac{1620}{1+1.15e^{-0.042t}}\\=\frac{1620}{1+\frac{1.15}{e^{0.042t}}}\\=\frac{1620}{1+\frac{1.15}{e^{0.042(\infty)}}}\\=\frac{1620}{1+\frac{1.15}{\infty}}\\=\frac{1620}{1+0}\\=\frac{1620}{1}\\=1620$