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Dimas [21]
3 years ago
10

Solve this problem ........... ​

Mathematics
1 answer:
Nutka1998 [239]3 years ago
7 0

Answer:

40.5

Step-by-step explanation:

\frac{2^3*3^4*4}{2*32} \\\\Firstly\ we\ have\ to \ expand\ the\ terms\ as\ factors:\\\\=\frac{(2*2*2)*(3*3*3*3)*(2*2)}{(2)*(2*2*2*2*2)`}\\\\We\ cancel \ terms\ that \ are\ common\ to \ both \ numerator\ and\ denominator\ to\ get:\\\\=\frac{3*3*3*3}{2}\\\\ =\frac{81}{2} \\\\We\ simplify\ the\ terms\ to \ its\ lowest\ form:\\\\=40.5

Therefore the answer to the problem = 40.5

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What are the restrictions for (x^2+10x+25)/(x^2-3x-28)<br><br> 0,14<br> -4,7<br> 0,7<br> 4,7
nirvana33 [79]
The answer is -4,7

The denominator can't equal zero. Factor the denominator:
x^2 - 3x - 28=
(X - 7)(x + 4); next set each set of parentheses equal to 0;
x - 7 = 0; so x=7 is one value
x + 4 = 0; so x=-4 is the other
Remember, x = 7 and x= -4 make the denominator zero, which is a "restriction" because you can't divide by zero.
5 0
3 years ago
Multiply and subtract these polynomials and simplify. Enter your response in standard form. (2x^3 − 3x + 11) − (3x^2 + 1)(4 − 8x
Lera25 [3.4K]

Answer:

=26x^3−12x^2+5x+7

Step-by-step explanation:

2x^3−3x+11−(3x^2+1)(4−8x)

Distribute:

=2x^3+−3x+11+24x^3+−12x^2+8x+−4

Combine Like Terms:

=2x^3+−3x+11+24x^3+−12x2+8x+−4

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5 0
4 years ago
Read 2 more answers
Can anyone teach mee..................... ​
andrew11 [14]

Answer:

(i) The name of the part of the circle, OQ is a radius

(ii) The radius of the sector QOR is 21 cm

Step-by-step explanation:

The given figure is a sector of the circle O

∵ Any sector of a circle formed from 2 radii and an arc

∴ OQ is a radius

(i) The name of the part of the circle, OQ is a radius

The rule of the length of an arc of a circle is L = \frac{\alpha }{360} × 2 π r, where

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∵ The length of the arc QR is 22 cm

∴ L = 22

∵ The measure of the angle of the arc is 60°

∴ α = 60°

∵ π = \frac{22}{7}

→ Substitute them in the rule above

∵ 22 = \frac{60}{360} × 2 × \frac{22}{7} × r

∴ 22 = \frac{22}{21} r

→ Divide both sides by  \frac{22}{21}

∴ 21 = r

(ii) The radius of the sector QOR is 21 cm

5 0
3 years ago
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Answer:

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Hope this helps.

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