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Dimas [21]
3 years ago
10

Solve this problem ........... ​

Mathematics
1 answer:
Nutka1998 [239]3 years ago
7 0

Answer:

40.5

Step-by-step explanation:

\frac{2^3*3^4*4}{2*32} \\\\Firstly\ we\ have\ to \ expand\ the\ terms\ as\ factors:\\\\=\frac{(2*2*2)*(3*3*3*3)*(2*2)}{(2)*(2*2*2*2*2)`}\\\\We\ cancel \ terms\ that \ are\ common\ to \ both \ numerator\ and\ denominator\ to\ get:\\\\=\frac{3*3*3*3}{2}\\\\ =\frac{81}{2} \\\\We\ simplify\ the\ terms\ to \ its\ lowest\ form:\\\\=40.5

Therefore the answer to the problem = 40.5

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A collection of nickels and quarters is worth 2.85 . There are 3 more nickels than quarters how many nickels and quarters are th
Zolol [24]

A nickel is equal to 5 cents or 0.05 dollars.

A quarter is equal to 25 cents or 0.25 dollars.

Let number of nickels be = n

Let number of quarters be = q

0.05n+0.25q=2.85    ...........(1)

As it is given, there are 3 more nickels than quarters so equation becomes,

n=q+3   ................(2)

Plug in the value of 'n' from (2) in (1)

0.05(q+3)+0.25q=2.85

= 0.05q+0.15+0.25q=2.85

0.30q=2.70

q=9

As n=q+3 we get, n=9+3=12

Hence, there are 12 nickels and 9 quarters.

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Answer:

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Step-by-step explanation:

Hope this helps? :)

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