The answer would be 50000000000000
Answer:
The launch angle should be adjusted to 30.63°
Step-by-step explanation:
The range of a projectile which is the horizontal distance covered by the projectile can be expressed as;
R =(v^2 sin2θ)/g
Where
R = range
v = initial speed
θ = launch angle
g = acceleration due to gravity
For the case above. When the projectile is launched at angle 13° above the horizontal.
θ1 = 13
R1 = (v^2 sin2θ1)/g
R1 = (v^2 sin26°)/g ....1
For the range to double
R2 = (v^2 sin2θ)/g .....2
R2 = 2R1
Substituting R2 and R1
(v^2 sin2θ)/g = 2 × (v^2 sin26°)/g
Divide both sides by v^2/g
sin2θ = 2sin26
2θ = sininverse(2sin26)
θ = sininverse(2sin26)/2
θ = 30.63°
Answer:
An x-coordinate is the x value in an ordered pair, which is just two mathematical objects, such as numbers, paired together. ... For instance, in the ordered pair (2,5), the x-coordinate would be '2. ' This value tells you how far a point is from the origin, or starting point, in the x direction on a 2-dimensional graph.
Step-by-step explanation:
Answer:
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honestly I couldn't make that
Answer:
1.-4,-1,1,6
2.by substituting the values given, we get
32-|15+8|
32-|23|
32-23=9
3.-15+7=8
4..27-(-12)=27+12=39
5.-6.05+(-2.1)
-6.05-2.1=-8.15
6.-3/4-(-2/5)
-3/4+2/5
=-7/20
7.-9(-12)
=108
8.(3.8)(-4.1)
-15.58
9.(-8x)(-2y)+(-3y)(z)
(16xy)+(-3zy)
(16xy)-(3zy)
10.by substituting the value given,we get
2.5*(-3.2)+5
-8+5
-3
so here are the answers,mark as brainliest if u find it useful
thank you
