Answer:
KE = 1/2 mv v^{2}
Explanation:
Sorry if this didn't helped you.
The frictional torque exerted on the platform by the axle as the platform rotates will be;
![\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]](https://tex.z-dn.net/?f=%5Crm%20T_f%20%5Ctheta%20%3D%5Cfrac%7B1%7D%7B2%7D%20I%20%5B%5Comega%5E2-%5Comega_0%5E2%5D)
<h3>What is torque?</h3>
Torque is the force's twisting action about the axis of rotation. Torque is the term used to describe the instant of force. It is the rotational equivalent of force. Torque is a force that acts in a turn or twist.
The amount of torque is equal to force multiplied by the perpendicular distance between the point of application of force and the axis of rotation.
Work done by the frictional torque = Change in the rotational kinetic energy of the wheel
![\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]](https://tex.z-dn.net/?f=%5Crm%20T_f%20%5Ctheta%20%3D%5Cfrac%7B1%7D%7B2%7D%20I%20%5B%5Comega%5E2-%5Comega_0%5E2%5D)
Where,
is the frictional torque
is the final angular velocity
is the initial angular velocity
is the angular displacement
Hence, the frictional torque exerted on the platform by the axle as the platform rotates will be;
![\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]](https://tex.z-dn.net/?f=%5Crm%20T_f%20%5Ctheta%20%3D%5Cfrac%7B1%7D%7B2%7D%20I%20%5B%5Comega%5E2-%5Comega_0%5E2%5D)
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The prime factors that affect the ability of substances to transfer the thermal energy to heat are the temperature difference between the two objects, area of cross-section, time, and distance travelled by the thermal energy.
<u>Explanation:
</u>
The process of heat conduction takes place through contact between two or more objects. But this conduction depends on multiple factors that are responsible for thermal conduction. They are-
- Temperature Difference(
) - The two objects must have a temperature difference else there will be no thermal conduction between them. The more the difference in their temperatures, the more thermal energy flows from one object to the other.
- Area of Cross-section (A) - Larger areas of contact provide as better medium of thermal conduction.
- Time (t) - The more time we give for the thermal conduction, the more energy is transmitted from one system to the other.
- Distance Travelled (l) - The longer the distance, lesser the conduction. Means, the distance should be minimized in order to achieve the optimum thermal conduction between two objects.
Consider metal pot and its handle, it is being boiled for 15 m. The molecules present near the source of heat, showing fast vibration and bounce off. It actually indicates the heats of substance. That’s why, handle remains hot as heat conduction takes place. It can be estimated by,

k - Thermal conductivity of the material, measured in J/s.m.
<h2>Given :-</h2>
<h2>To Find :-</h2>
<h2>Solution :-</h2>
As we know that,
<h3>F = ma</h3>
- F is the Force applied
- M is the Mass
- A is the Acceleration
<u>According</u><u> </u><u>to</u><u> </u><u>the question</u><u>, </u>
F = 20 × 2
F = 40 N
<h3>Hence :-</h3>
Force applied is 40 N
<h2>Know More :-</h2>
- First equation of motion
- v = u + at
- Second equation of motion
- s = ut + ½at²
- Third Equation of motion
- v² - u² = 2as

The centripetal acceleration of the tip of the fan blade is 96.23 m/s²
<h3>What is centripetal acceleration?</h3>
The acceleration developed when a body is moving in circular way, directed towards the center of the circular path.
The tip of a fan blade is 0.61 m from the center of the fan. the fan turns at a constant speed and completes 2 rotations every 1.0 s
ac = ω²r
where ω = angular speed = 2πN/60, N = Rotation per minute
From the question, N = 2 x 60/1 = 120 RPM
So, the angular speed will be
ω = 2π x 120 /60
ω = 12.56 rad/s
Then, the centripetal acceleration is
ac = (12.56)² x 0.61 m
ac = 96.23 m/s²
Thus, centripetal acceleration of the tip of the fan blade is 96.23 m/s²
Learn more about centripetal acceleration
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