At a speed 343 m/s and frequency of 536 Hz;
the wavelength is computed by velocity / frequency = 343 /
536 = 0.640 m or 64 cm
If the tube is open at the top there is a concentrated at the top and a node at
the bottom at resonance.
i.e: at L = lambda / 4
The next resonance happens at 3 lambda/4 then 5 lambda/4 etc.
these resemble to 64 / 4 = 16 cm.
therefore,
the lengths from the open end to the water level corresponding to the first 2:
L1 = v / 4f = 343 / 4*536 = 16cm
L2 = 3v / 4f = 3*343 / 4*536 = 48 cm
Pv= nRT; n/V = p/rt; g/liter = moles/liters * 29.0g/mole
Answer:
Induced emf in the rod is, 
Explanation:
Given that,
Length of the rod, L = 22 cm = 0.22 m
Angle with x axis is 37.9 degrees with the positive x-axis and an angle of 52.1 degrees with the positive y-axis.
Velocity of the rod, v = 6.8i m/s
Magnetic field, 
The formula for the emf induced in the rod is given by :
So, the magnitude of the emf induced in the rod is 0.08262 volts. Hence, this is the required solution.
Answer:
The centripetal force on the boy = 2.888 N
Explanation:
Given:
m = 30 kg
r = 1.5 m
v = 0.38 m/s
To Find:
The centripetal force on the boy = ?
Solution:
F = m x v^2 / r
F = 30 kg x (0.38 m/s)^2 / 1.5 m
F = 30 x 0.1444 / 1.5
F = 2.888 N
Therefore,
The centripetal force on the boy = 2.888 N
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Answer: 8400 J
Explanation:
The formula referenced in the question is:
Where:
is the thermal energy
is the mass of the water sample
is the specific heat capacity of water
is the variation in temperature
Solving:
This is the thermal energy released
