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olga nikolaevna [1]
3 years ago
10

What is the formula of kinetics?​

Physics
1 answer:
snow_lady [41]3 years ago
4 0

Answer:

KE = 1/2 mv v^{2}

Explanation:

Sorry if this didn't helped you.

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A vertical piston-cylinder device initially contains 0.1 m^3 of air at 400 K and 100 kPa. At this initial condition, the piston
jenyasd209 [6]

Answer:

Q=-38.15kJ

Explanation:

From the question we are told that

Piston-cylinder initial Volume of air v_1=0.1 m^3

Piston-cylinder initial temperature T_1=400k

Piston-cylinder initial pressure P_1= 100kpa

Supply line temperatureT_s=400k

Supply line pressure P_s= 500kpa

Valve  final pressure P_v=500kpa

Piston movement pressure P_m=200kpa

Piston-cylinder final Volume of airv_2=0.2 m^3

Piston-cylinder final temperature T_2=440k

Piston-cylinder final pressure P_2= 500kpa

Generally the  equation for conservation of mass is mathematically given by

Q=m_2 \mu_2-m_1 \mu_1 +W-(m_2-m_1)h

where

Initial moment

m_1=\frac{p_1 V_1}{RT_1}

m_1=\frac{100*0.1}{0.287*400}

m_1=8.7*10^-^2kg

Final moment

m_2=\frac{p_2 V_2}{RT_2}

m_1=\frac{500*0.3}{0.287*440}

m_1=79*10^{-2}kg

Work done by Piston movement pressure

W=Pd

W=P(v_2-v_1)

W=200(0.2-0.1))

W=20000J

Heat function

h=cT_1

h=1.005(400)

h=402

Therefore

Q=(0.792*0.718(440)-0.0871*0.718(400)+20-(0.792-0.087)*402))

Q=-38.15kJ

It is given mathematically that the system lost  or dissipated Heat of

Q=-38.15kJ

7 0
3 years ago
A proton moves north with a speed of 3 x 10^6 m/s. A 5 Tesla magnetic field is directed west. Determine the magnitude and direct
Andreyy89

The magnitude of magnitude force on the proton is 2.4 x 10⁻¹² N.

<h3>Magnitude of magnetic force on the proton</h3>

The magnitude of magnitude force on the proton is calculated as follows;

F = qvB sinθ

where;

  • q is the charge of the proton
  • v is the speed of the proton
  • B is the magnitude of the magnetic filed
  • θ is the angle between the field and speed

Substitute the given parameters and solve for the magnetic force.

F = (1.6 x 10⁻¹⁹) x (3 x 10⁶) x (5) X(sin90)

F = 2.4 x 10⁻¹² N

Thus, the magnitude of magnitude force on the proton is 2.4 x 10⁻¹² N.

Learn more about magnetic force here: brainly.com/question/13277365

7 0
3 years ago
Question 1 options:
Genrish500 [490]

Answer:

Steam engines to operate using only hot steam

Explanation: i took the quiz

5 0
3 years ago
What is the magnitude of the force a 25 charge exerts on a 3 mc charge 35cm away?
lara31 [8.8K]
The electrostatic force between two charges is given by
F=k_e  \frac{q_1 q_2}{r^2}
where
ke is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the charges

In our problem, 
q_1 = 25 \mu C=25 \cdot 10^{-6} C
q_2 = 3 mC = 3 \cdot 10^{-3} C
r=35 cm=0.35 m
Therefore the electrostatic force is
F=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(25 \cdot 10^{-6}C)(3 \cdot 10^{-3}C)}{(0.35 m)^2}= 5510 N
4 0
4 years ago
Which city has already hosted the Olympic Games three times?
____ [38]
London, it has hosted the 1908, 1948 and the 2012 summer olympics
8 0
4 years ago
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