Answer:
Write the following Quantitiesin scientific notation.
a. 10130 Pa to 2 decimal place
b. 978.15m * s-2 to one decimal place
c 0.000001256 A to3 decimal place
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Answer: a.
b.
c.
Explanation:
Scientific notation is defined as the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.
For example : 5000 is written as
a. 10130 Pa to 2 decimal place is written as
b. to 1 decimal place is written as
c. to 3 decimal places is written as
Explanation:
Relative to the positive horizontal axis, rope 1 makes an angle of 90 + 20 = 110 degrees, while rope 2 makes an angle of 90 - 30 = 60 degrees.
By Newton's second law,
- the net horizontal force acting on the beam is
![R_1 \cos(110^\circ) + R_2 \cos(60^\circ) = 0](https://tex.z-dn.net/?f=R_1%20%5Ccos%28110%5E%5Ccirc%29%20%2B%20R_2%20%5Ccos%2860%5E%5Ccirc%29%20%3D%200)
where
are the magnitudes of the tensions in ropes 1 and 2, respectively;
- the net vertical force acting on the beam is
![R_1 \sin(110^\circ) + R_2 \sin(60^\circ) - mg = 0](https://tex.z-dn.net/?f=R_1%20%5Csin%28110%5E%5Ccirc%29%20%2B%20R_2%20%5Csin%2860%5E%5Ccirc%29%20-%20mg%20%3D%200)
where
and
.
Eliminating
, we have
![\sin(60^\circ) \bigg(R_1 \cos(110^\circ) + R_2 \cos(60^\circ)\bigg) - \cos(60^\circ) \bigg(R_1 \sin(110^\circ) + R_2 \sin(60^\circ)\bigg) = 0\sin(60^\circ) - mg\cos(60^\circ)](https://tex.z-dn.net/?f=%5Csin%2860%5E%5Ccirc%29%20%5Cbigg%28R_1%20%5Ccos%28110%5E%5Ccirc%29%20%2B%20R_2%20%5Ccos%2860%5E%5Ccirc%29%5Cbigg%29%20-%20%5Ccos%2860%5E%5Ccirc%29%20%5Cbigg%28R_1%20%5Csin%28110%5E%5Ccirc%29%20%2B%20R_2%20%5Csin%2860%5E%5Ccirc%29%5Cbigg%29%20%3D%200%5Csin%2860%5E%5Ccirc%29%20-%20mg%5Ccos%2860%5E%5Ccirc%29)
![R_1 \bigg(\sin(60^\circ) \cos(110^\circ) - \cos(60^\circ) \sin(110^\circ)\bigg) = -\dfrac{mg}2](https://tex.z-dn.net/?f=R_1%20%5Cbigg%28%5Csin%2860%5E%5Ccirc%29%20%5Ccos%28110%5E%5Ccirc%29%20-%20%5Ccos%2860%5E%5Ccirc%29%20%5Csin%28110%5E%5Ccirc%29%5Cbigg%29%20%3D%20-%5Cdfrac%7Bmg%7D2)
![R_1 \sin(60^\circ - 110^\circ) = -\dfrac{mg}2](https://tex.z-dn.net/?f=R_1%20%5Csin%2860%5E%5Ccirc%20-%20110%5E%5Ccirc%29%20%3D%20-%5Cdfrac%7Bmg%7D2)
![-R_1 \sin(50^\circ) = -\dfrac{mg}2](https://tex.z-dn.net/?f=-R_1%20%5Csin%2850%5E%5Ccirc%29%20%3D%20-%5Cdfrac%7Bmg%7D2)
![R_1 = \dfrac{mg}{2\sin(50^\circ)} \approx \boxed{8300\,\rm N}](https://tex.z-dn.net/?f=R_1%20%3D%20%5Cdfrac%7Bmg%7D%7B2%5Csin%2850%5E%5Ccirc%29%7D%20%5Capprox%20%5Cboxed%7B8300%5C%2C%5Crm%20N%7D)
Solve for
.
![\dfrac{mg\cos(110^\circ)}{2\sin(50^\circ)} + R_2 \cos(60^\circ) = 0](https://tex.z-dn.net/?f=%5Cdfrac%7Bmg%5Ccos%28110%5E%5Ccirc%29%7D%7B2%5Csin%2850%5E%5Ccirc%29%7D%20%2B%20R_2%20%5Ccos%2860%5E%5Ccirc%29%20%3D%200)
![\dfrac{R_2}2 = -mg\cot(110^\circ)](https://tex.z-dn.net/?f=%5Cdfrac%7BR_2%7D2%20%3D%20-mg%5Ccot%28110%5E%5Ccirc%29)
![R_2 = -2mg\cot(110^\circ) \approx \boxed{9300\,\rm N}](https://tex.z-dn.net/?f=R_2%20%3D%20-2mg%5Ccot%28110%5E%5Ccirc%29%20%5Capprox%20%5Cboxed%7B9300%5C%2C%5Crm%20N%7D)
Answer:
3: I can´t see the text/image, but it depend on the mass and the force applied to the ball, if both are too high, it will be harder to make a home run. (Second law)
4:It would be easier to make a home run because there is no interruption between the ball and the space the same travels. (Third law)
Explanation:
Answer:
continental drift
Explanation:
Wegener proposed that the continents plowed through crust of ocean basins, which would explain why the outlines of many coastlines look like they fit together like a puzzle
The answer is full moon because that’s how it changes in life