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Nimfa-mama [501]
3 years ago
11

new vintage 1965 convertible requires an ol change every 400 miles and replacement of all fBuids every 13,000 mles If these serv

ices have pust been performed by the dealer, how many mles from now will both be due at the same tme? The services will both be due at the same ime agan in mdes (Type a whole rumber)
Mathematics
1 answer:
tekilochka [14]3 years ago
3 0

Answer: There are 26000 miles that will both be due at the same time.

Step-by-step explanation:

Since we have given that

Number of miles required by new vintage = 400

Number of miles if these services have must been performed by the dealer = 13000

We need to find the number of miles from now that will both be due at the same time.

We would use "LCM of 400 and 13000":

As we know that LCM of 400 and 13000 is 26000.

So, there are 26000 miles that will both be due at the same time.

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Mick dropped 2 pennies and he had 7 how many does he have left
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Answer:

5

Step-by-step explanation:


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3 years ago
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Find the value of the variable if P is between J & K. A) JP = 8z - 17 B) PK = 5z + 37 C) JK = 17z - 4
Daniel [21]
<span>We cannot deduce about the exact location of P between J and K. But we can conclude: segment JP + segment PK = line JK.
</span><span>JP + PK = JK.
</span><span>Substitute first each.
(8z - 17) + (5z + 37) = 17z - 4
Combine like terms.
13z + 20 = 17z - 4
Isolate the variable z.
4z = 24
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Step-by-step explanation:

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4 0
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observe as seguintes situações e sua representação em linguagem matematica dois numeros x e y são tais 2x y=6 x-y=3
agasfer [191]

Answer:

The value of x any y are "-5.29 and 0.79" and "3.79 and -2.29"

Step-by-step explanation:

Given values:

2xy =6.....(a)\\\\x-y= 3.....(b)\\\\

After solve equation (a) we get

\ equation: \\\\2xy= 6\\\\xy =\frac{6}{2} \\\\xy = 3.....(x)\\\\

After solve equation (b) we get

\ equation: \\\\x-y =3\\\\x= 3+y....(x1)\\

put the value of x in to equation (x)

(3+y)y = 3\\

y^2+3y-3=0\\\\\ compare \ the \ value \ with \ ay^2+by+c=0\\a= 1\\b=3\\c=-3\\\ Formula: \\y= \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\y= \frac{-3\pm \sqrt{9+12}}{2}\\y= \frac{-3\pm \sqrt{21}}{2}\\

The value of y is = -5.29 and 0.79, put the value of y in x1 equation so, we get: 3.79 and -2.29

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3 years ago
Solve the inequality 3(x+2)&gt;0
Goryan [66]
Distribute
3x+6>0

Subtract 6 from both sides
3x>-6

Divide both sides by 3
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Final answer: x>-2
4 0
4 years ago
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