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Alisiya [41]
3 years ago
7

Y varies directly with the square of X.If y =5 when x=3,what is the value of y when x=9?​

Mathematics
1 answer:
natta225 [31]3 years ago
5 0

Answer:45

Step-by-step explanation:

y varies directly as x^2

y=k x x^2

When y=5 x=3

5=k x 3^2

5=k x 9

K=5/9

Relationship is y=5x^2/9

y=(5x9^2) ➗ 9

y=(5x81) ➗ 9

y=405 ➗ 9

y=45

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