Answer:
Volume of pure Acid in -50- LITRES of the solution= 10- litres. Let “V”- litres of water be added, then
Therefore 10= (50+ V) x8/100 .
So 10= 4 + 8V/100
8V/100 = 10–4= 6
So V= 6 x 100/8= 600/8= 75- LITRES.
So on adding 75- litres of water to the acid solution, the percentage of acid drops to 8% .
Check: Percentage of acid in 125- LITRES of acid solution, which contain 10- LITRES if pure Acid
= 10/125 x 100= 8% .
Step-by-step explanation:
I’m pretty sure you just solve exactly like that
-7(-2)-1 =13 at least I’m told that \_( •-• )_/
M + s + r = 8500
5m + 6s + 8.50r = 64600
s = 2m
m + 2m + r = 8500
3m + r = 8500
r = 8500 - 3m
5m + 6(2m) + 8.50(8500 - 3m) = 64600
5m + 12m + 72250 - 25.50m = 64600
-8.50m = 64600 - 72250
-8.50m = -7650
m = -7650 / - 8.50
m = 900 <=== 900 matinee tickets
s = 2m
s = 2(900)
s = 1800 <===1800 student tickets
r = 8500 - 3m
r = 8500 - 3(900)
r = 8500 - 2700
r = 5800 <=== regular
Answer: C
Step-by-step explanation:
The line 
is shaded below and is solid.
This eliminates all the options except for C.
