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aleksley [76]
3 years ago
7

If a person walks 1/3 mile in 15 minutes, how far will that person walk in one hour? (ik im dumb dont need to say it.)

Mathematics
1 answer:
Rainbow [258]3 years ago
7 0

Answer:

1 and 1/3 miles in an hour

Step-by-step explanation:

thats slow, ive walked a mile in ten minutes, lol

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Solve for x.<br><br> −5(x−4)=−30<br><br> Enter your answer in the box.
saveliy_v [14]
First divide both sides by - 5,

x - 4 = 6

Move the constant to the right side of the equation and change its sign (-4 => +4)

x = 6 + 4

Add the numbers,

x = 10

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I hope that helps you out!!

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3 years ago
A car runs 20mph how much does it travel in 1 hour
Effectus [21]
The answer is in the question itself... so since it says 20 miles per hour that’s the distance it covers per hour. the answer would be it travels 20 miles in an hour
5 0
3 years ago
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An average of 20 pears were sold from Monday to Friday. After the sales on Saturday and Sunday, the average pears sold per day w
Fittoniya [83]

Answer:

5 pears

Step-by-step explanation:

Given that

The  average of 20 pears were sold from Monday to Friday

But after the sales on Saturday and Sunday, the average pears sold per day were increased to 25

We need to determine the number of pears sold on Saturday and sunday

So, it is

= 25 pears - 20 pears

= 5 pears

4 0
3 years ago
PLEASE HELP ME PLEASE HELP ME WITH MY MATH
ryzh [129]
A. I would estimate that 7 in of the ribbon
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5 0
3 years ago
In triangle ABC shown below, DE is parallel to AC. The following two-column proof with missing statements and reasons proves tha
lianna [129]

Answer:

The correct option is;

C. 3. ∠BDE ≅∠BAC, Corresponding Angles Postulate 4. ∠B ≅ ∠B Reflexive Property of Equality

Step-by-step explanation:

The two column proof can be written as follows;

Statement,                         Reason

1. \overline{DE} \parallel \overline{AC},                           Given

2. \overline {AB} is a transversal ,         Conclusion from statement 1.

We note that ∠BDE  and ∠BAC are on the same side of the transversal relative to the parallel lines, and are therefore, corresponding angles.

Therefore, we have;

3. ∠BDE ≅∠BAC,                 Corresponding Angles Postulate

Also

4. ∠B ≅ ∠B,                           Reflexive Property of Equality

In the two triangles, ΔABC and ΔDBE, we have ∠BDE ≅∠BAC and ∠B ≅ ∠B,

From ∠BDE + ∠B + ∠BED = 180°

∠BAC + ∠B +  ∠BCA = 180°

Therefore, ∠BED = ∠BCA Substitution property of equality

Which gives;

5, ΔABC ~ ΔDBE,          Angle Angle Similarity Postulate

6. BD/BA = BE/BC,      Converse of the Side-Side-Side Similarity Theorem

5 0
3 years ago
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