Question

Length of a rectangle is four times its width if the area of the rectangle is 196 yards find its perimeter

Answer 1

Answer:

21 yd

Step-by-step explanation:

Length of a rectangle is four times its width =

L = 4 × w

The area of the rectangle is 196

L = 4W

A = L*W = 196

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4W*W = 196

W*W = 196/4

W*W = 49

W = 7

L = 28

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Answer:

P = 2(L + W)

P = 2(28 + 7)

P = 14 + 7

P = 21 yd

Answer 2

Answer:

22 yd

Step-by-step explanation:

Length is four times its width   ----->    L=4W

area of rectangle is 196           ----->   196=LW

Plug L=4W into 196=LW giving you 196=(4W)W

Simplify a bit 196=4W^2

Divide both sides by 4:   196/4=W^2

Simplify a bit:   49=W^2

Square root both sides:  7 or -7=W

The width is 7 yd

The length is 4(7)=28 yd

Now its final part is for you to find the perimeter of this rectangle.  The rectangle is a 7 yd by 4 yd rectangle.

Double both then add.. 14+8=22 yd