Length of a rectangle is four times its width if the area of the rectangle is 196 yards find its perimeter
2 answers:
Answer:
21 yd
Step-by-step explanation:
Length of a rectangle is four times its width =
L = 4 × w
The area of the rectangle is 196
L = 4W
A = L*W = 196
---
4W*W = 196
W*W = 196/4
W*W = 49
W = 7
L = 28
---
Answer:
P = 2(L + W)
P = 2(28 + 7)
P = 14 + 7
P = 21 yd
Answer:
22 yd
Step-by-step explanation:
Length is four times its width -----> L=4W
area of rectangle is 196 -----> 196=LW
Plug L=4W into 196=LW giving you 196=(4W)W
Simplify a bit 196=4W^2
Divide both sides by 4: 196/4=W^2
Simplify a bit: 49=W^2
Square root both sides: 7 or -7=W
The width is 7 yd
The length is 4(7)=28 yd
Now its final part is for you to find the perimeter of this rectangle. The rectangle is a 7 yd by 4 yd rectangle.
Double both then add.. 14+8=22 yd
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the answer: (-5; 17)
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m(2g+5mk)
rationalise 29302/100000
=14651/50000
1.5 cleaner / 12 cups of water
or
1.5 cleaner : 12 cups of water
to reduce this ratio of 1.5:12, we need to divide both by the same number
1.5 divided by 1.5 is 1
12 divided by 1.5 is 8
So the ratio of cleaner to water is 1:8 in its simplest form or 1 part cleaner to 8 parts water.
Hope this helps!! :)