Answer:
12
Step-by-step explanation:
1st of all we should let the ration of boys to girls be 2x and 3x.
After that we should make the sum between 2x and3×and the sum of 2numbers is equal to 30
i.e.2x+3x=30
Then ,by solving this eqation we get the value of x=6
After that put the value of x in the number of boys
i.e.
2x=2×6=12
Hence ,the number of boys is 12
Answer: 1733.33 ≈ 1734 applicants
Step-by-step explanation:
Let x be the number of job applicants being looked at.
If 25% of applicants become job candidates, then number of job candidates = 0.25x
If 20% of job candidates receive job offers, then the number of job offers = 0.20 × 0.25x = 0.05x
If 75% of job offers are accepted, then number of accepted recruits = 0.75 × 0.05x = 0.0375x
This 0.0375x shows the number of new recruits which is equivalent to the 65 that is needed by the client if the recruiter.
By equating this 0.0375x to 65,we have:
0.0375x = 65
x = 65/0.0375
x= 1733.33 applicants, for whole number sake because we're dealing with humans, we approximate to 1734
The answer for this equation is 25
Answer:
28 units²
Step-by-step explanation:
→ Work out the size of the triangle if it was a full rectangle
Height = 4 and Base = 2
→ Work out area of triangle
0.5 × Height × Base ⇒ 0.5 × 4 × 2 ⇒ 2 × 2 ⇒ 4
→ Minus the area of the triangle from the "imaginary full' rectangle
Area of rectangle = Length × Width ⇒ 8 × 4 ⇒ 32
32 - 4 = 28
Answer:
acute: 7, 9
right: 8, 10
obtuse: 5, 6
Step-by-step explanation:
When you have a number of identical calculations to do, it is convenient to do them in a spreadsheet. You only need to enter the formula once and copy it as many times as needed.
The attachment shows the "sum of squares" calculation and comparison to the square of the longest side. When the sum is too small, the longest side is longer than needed for a right angle, so the triangle is obtuse. When the sum is too great, the longest side is too short for a right angle, so the triangle is acute.
We have skipped the tedious arithmetic and shown the results in the attached table.