At point of intersection the two equations are equal,
hence, 6x³ =6x²
6x³-6x²=0
6x²(x-1)=0 , the values of x are 0 and 1
The points of intersection are therefore, (0,0) and (1,6)
To find the slopes of the tangents at the points of intersection we find dy/dx
for curve 1, dy/dx=12x, and the other curve dy/dx=18x²
At x=0, dy/dx=12x =0, dy/dx=18x² = 0, hence the angle between the tangents is 0, because the tangents to the two curves have the same slope which is 0 and pass the same point (0,0) origin.
At x=1, dy/dx =12x = 12, dy/dx= 18x² =18, Hence the angle between the two tangents will be given by arctan 18 -arctan 12
= 86.8202 - 85.2364 ≈ 1.5838, because the slope of the lines is equal to tan α where α is the angle of inclination of the line.
Answer:
1. 2/6 or 1/3
2. 4/6 or 2/3
3. 3/6 or 1/2
Step-by-step explanation:
I hope this helps I did the ones I knew
9xa is the common factor.
You can complete the statement by dividing the two terms of the expression of the left side by 9xa, and you will get:
36x^3a + 45xa^2 = 9xa ( 4x^2 + 5a)
#5 is 5 days
40×5=200
200+150=250
20×5=100
100+150=250
Answer:
5
Step-by-step explanation:
150/30 = 15/3 = 5
Good luck!
