What number is this 5 x 10 ^2 + 3

Mathematics

2 answers:

butalik [34]3 years ago

5 0

Answer:

503 is the answer

Step-by-step explanation:

If you use Pemdos you have to start by doing the exponent then you multiply then after that you will have to do addition and that is how you get your answer

Mekhanik [1.2K]3 years ago

5 0

Answer:

503

Step-by-step explanation:

Ok, to tackle this problem we are going to take it section by section. First what we are going to do is apply PEMDAS (Parentheses, Exponent, Multiplication, Divison, Addition Subtarction) to this probelm and solev in taht order.

We see that the 10 has an exponnet of 2, so really this is just saying 10 to the power of 2, or 100.

Then we would solve the rest of the equation.

5(100)+3

And we get an answer of 503

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Find the x intercept of the parabola with vertex 3,-2 and y intercept 0,7 round to the nearest hundredth

12345 [234]

An x-intercept is namely a "solution" or "zero" or "root" often called, and when that happens, y = 0, just like with any other x-intercept.

$\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
\boxed{y=a(x- h)^2+ k}\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
\begin{cases}
h=3\\
k=-2
\end{cases}\implies y=a(x-3)^2-2
\\\\\\
\textit{we also know that }
\begin{cases}
x=0\\
y=7
\end{cases}\implies 7=a(0-3)^2-2
\\\\\\
9=9a\implies \cfrac{9}{9}=a\implies 1=a\qquad therefore\qquad \boxed{y=(x-3)^2-2}$

so what is its x-intercept anyway?

$\bf \stackrel{y}{0}=(x-3)^2-2\implies 2=(x-3)^2\implies \pm\sqrt{2}=x-3
\\\\\\
\pm\sqrt{2}+3=x\qquad therefore\qquad (\pm\sqrt{2}+3~~~~,~~~~0)$

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Snezhnost [94]

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Read 2 more answers

X-(-27)=35-12 solving equation

irakobra [83]

-4 is the correct answer
35-12 =25
-4 - ( -27) = -4 + 27 =23

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