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3 years ago

What number is this 5 x 10 ^2 + 3

Mathematics

2 answers:

butalik [34]3 years ago

5 0

Answer:

503 is the answer

Step-by-step explanation:

If you use Pemdos you have to start by doing the exponent then you multiply then after that you will have to do addition and that is how you get your answer

Mekhanik [1.2K]3 years ago

5 0

Answer:

503

Step-by-step explanation:

Ok, to tackle this problem we are going to take it section by section. First what we are going to do is apply PEMDAS (Parentheses, Exponent, Multiplication, Divison, Addition Subtarction) to this probelm and solev in taht order.

We see that the 10 has an exponnet of 2, so really this is just saying 10 to the power of 2, or 100.

Then we would solve the rest of the equation.

5(100)+3

And we get an answer of 503

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I need help with this please

djyliett [7]

Answer:

Step-by-step explanation:

The last three are irrational but I'm not sure about the first four.

3 0

3 years ago

use the fact that 10^3 = 2^10 to mentally find a vaule of n for which 2^n > 10^50 & 10^n > 2^300

Rudiy27

$2^n>10^{50}=10^{3\cdot16+2}=10^2(10^3)^{16}=10^2(2^{10})^{16}=5^22^{162}$
$2^{n-162}>25$

The least power of 2 that exceeds 25 is $2^5=32$ , so we have

$2^{n-162}=2^N>25\implies N=5\implies n-162=5\implies n=167$

- - -

$10^n>2^{300}=(2^{10})^{30}=(10^3)^{30}=10^{90}$

The least integer $n$ that satisfies this inequality would clearly be $n=91$ .

6 0

3 years ago

Consider the surface given by

Mazyrski [523]

This is just simple. For example you have a plane of the form x=a, then you just substitute x with a, and you'll get an equation with y and z only, hence you have a 2-d trace of the intersection. It is just similar for y=b and z=c.

(1) At z=1.5, 2x^2 + 5y^2 + 1.5^2 = 4
2x^2 + 5y^2 = 1.75
Now you have an ellipse in the z=1.5 plane as your trace.

(2) At x=1, 2(1)^2 + 5y^2 + z^2 = 4
5y^2 + z^2 = 2
Now you have an ellipse in the x=1 plane as your trace.

(3) At z=0, 2x^2 + 5y^2 + (0)^2 = 4
2x^2 + 5y^2 = 4
Now you have an ellipse in the z=0 plane as your trace.

(4) At y=0, 2x^2 + 5(0)^2 + z^2 = 4
2x^2 + z^2 = 4
Now you have an ellipse in the y=0 plane as your trace.

5 0

4 years ago

Examine this system of equations. Which number can be multiplied by each equation so that when the two equations are

andreyandreev [35.5K]

Answer:

15 times the first equation and -12 times the second equation

Step-by-step explanation:

we have

$\frac{3}{4}x+\frac{2}{3}y=6$ ------> first equation

$\frac{5}{8}x+\frac{5}{6}y=12$ ------> second equation

Multiply the first equation by 15 both sides

$(15)\frac{3}{4}x+(15)\frac{2}{3}y=6(15)$

$\frac{45}{4}x+10y=90$ -----> new first equation

Multiply the second equation by -12 both sides

$(-12)\frac{5}{8}x+(-12)\frac{5}{6}y=12(-12)$

$-\frac{60}{8}x-10y=-144$ -----> new second equation

Adds the two new equations

$\frac{45}{4}x+10y=90\\-\frac{60}{8}x-10y=-144\\-----------\\\frac{45}{4}x-\frac{60}{8}x=90-144$

The y-term was eliminated

5 0

3 years ago

at the pet fair, Darlene's dog weighed 5 times as much as leah's dog. Together, the dogs weighed 84 pounds. how much did each do

Alex

Let x = Darlene's dog's weightlet y = Leah's dog's weight x = 5yx + y = 84 so, 5y + y = 84, which means 6y = 84 so, y = 84/6 = 14x = 5(14) = 70 Darlene's dog = 70 lbs, Leah's dog = 14 lbs.<span> </span>

4 0

4 years ago