Answer:
This is guess of what the question is asking:
I had got 49x - 21y - 6.
Step-by-step explanation:
7 x 7 is 49 and 7 x 3 is 21.
Answer:
7/6
Step-by-step explanation:
Answer: The graph of the function would move five units up on the vertical axis.
Step-by-step explanation:
These problems are called systems of equations. Basically you have two linear equations and you need to find the values for x and y. In other words, all these equation are lines and our answer will be the exact point that the pair of lines intersect. For example, if we get x=1 and y=2 the lines will intersect at point (1,2). Now that you have some background knowledge here comes the tricks and tactics kid.
We know that we can solve one variable equation easily. For example...
x+1=2
x=1 obviously
Cause we have two variables x and y it is not possible to find a solution. For example, in the equation x+y=10, x=1 when y=9 and x=2 when y=8. There is not correct answer.
So what can we do? We have to make a two variable equation into a one variable equation.
There are two ways to do this: substitution and elimination. I will create a sample problem and then solve it using both methods.
x+y=2
2y-y=1
3)
-3x-5y=-7 -----> -12x-20y=-28
-4x-3y=-2 ------> -12x-9y=-6
-12x-20y=-28
-(-12x-9y=-6)
---------------------
-11y=-22
y=2
-3x-5(2)=-7
-3x=3
x=-1
4) 8x+4y=12 ---> 24x+12y=36
7x+3y=10 ---> 28x+12y=40
28x+12y=40
-(24x+12y=36)
---------------------
4x=4
x=1
8(1)+4y=12
4y=4
y=1
5) 4x+3y=-7
-2x-5y=7 ----> -4x-10y=14
4x+3y=-7
+(-4x-10y=14)
-------------------
-7y=7
y=-1
4x+3(-1)=-7
4x=-4
x=-1
6) 8x-3y=-9 ---> 32x-12y=-36
5x+4y=12 ---> 15x+12y=36
32x-12y=-36
+(15x+12y=36)
--------------------
47x=0
x=0
8(0)-3y=-9
-3y=-9
y=3
7)-3x+5y=-2
2x-2y=1 ---> x-y=1/2 ----> x=y+1/2
-3(y+1/2)+5y=-2
-3y-1.5+5y=-2
2y=-0.5
y=0.25
2x-2(0.25)=1
2x=1.5
x=0.75
Answer:
Step-by-step explanation:
For standard form the circle's equation we need the centre of the circle and the radius.
Step 1: <em><u>Find the centre</u></em>
If the centre is not given find the end points of the diameter
and then find the mid point.
Let the end points of the diameter be : ( - 3 , 8 ) and ( -3 , -4 )
The mid-point of the diameter is :
Therefore, centre of the circle = ( -3 , 2 )
Step 2 : <u>Find radius</u>
<u></u>
<u></u>
Diameter is the distance between the end points ( -3 , 8) and ( -3 , -4 )
That is ,
Therefore ,
Step 3 : <u>Equation of the circle</u>
Standard equation of the circle with centre ( h ,k )
and radius ,r is :
Therefore, the equation of the circle with centre ( -3, 2)
and radius = 6 is :
