In the table shown below:
Let N be the number of bottles filled,
Let T be the time in hours.
Given that the number of bottles filled is proportional to the amount of time the machine runs, we have
Let's evaluate the value of k for each day.
Thus, on monday,
Tuesday:
Wednesday:
Thursday:
It is observed that all exept wednesday have the same value of k.
Thus, the amount of time required for the number of bottles filled on wednesday is evaluated as
Hence, the incorrect day is Wednesday. The amount of time for that many bottles should be 6.85 hours.
I’m assuming ‘dives further’ means to go directly down
the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.
let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)
then this become a simple trig problem:
A)
Let O be the position of of the ship, and C be the original position of the submarine.
therefore, not considering direction
|OC| = 1.78km = 1780m
|CA| = 45m
these are the adjacent and opposite sides of a right angled triangle.
But tan($) = opp/adj = |CA|/|OC| = 45/1780
therefore $ = arctan(45/1780) which is roughly 1.45 degrees,
B)
similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m
tan(¥) = 107/1780
¥ = arctan(107/1780) which is roughly 3.44 degrees
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8 because it goes from 1s 10s 100s so 8 is the answer
