2 years ago

What is the solution to the equation t minus 15 = 76?

Mathematics

1 answer:

Phoenix [80]2 years ago

8 0

Answer:

4. / D.

Step-by-step explanation:

$t-15=76\\t=76-15\\t=61$

You might be interested in

Help Please! Find the value of x for which ABCD must be a parallelogram.

Pepsi [2]

Answer:

Step-by-step explanation:

We know that the opposite sides of a parallelogram are equal so:

25x+1=7x+37

18x=36

x=2

4 0

2 years ago

Where do i graph it

Anuta_ua [19.1K]

(-5,-10)E
(-5,-3)F
(-3,-10)G

7 0

3 years ago

Read 2 more answers

HURRY PLEASE!! :( Find the 15th term: a(1) = 7; d = 3

My name is Ann [436]

Yes that is correct ma dude

6 0

3 years ago

Many credit card companies charge a compound interest rate of 1.8% per month on a credit card balance. Nelson owes $850 on a cre

Finger [1]

The sequence will be

$850, 850 \times (1.018)^1, 850 \times (1.018)^2, 850 \times (1.018)^3, 850 \times (1.018)^4, ...$

That's

$850, 865.30, 880.875, 896.731, 912.872, ...$

8 0

3 years ago

Read 2 more answers

Which answer best describes the complex zeros of the polynomial function?

marysya [2.9K]

Answer-

D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.

Solution-

The given polynomial is,

$f(x)=x^3-x^2+6x-6$

The zeros of the polynomials are,

$\Rightarrow f(x)=0$

$\Rightarrow x^3-x^2+6x-6=0$

$\Rightarrow x^2(x-1)+6(x-1)=0$

$\Rightarrow (x^2+6)(x-1)=0$

$\Rightarrow (x^2+6)=0,(x-1)=0$

$\Rightarrow x=\sqrt{-6},\ x=1$

$\Rightarrow x=1,\ \pm \sqrt6i$

Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1

3 0

3 years ago