$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \\ Here: \\ \\ f(x) = x^2 + 5x + 5 \\ \\ \\ So: \\ \\ a=1 \\ \\ b=5 \\ \\ c=5 \\ \\ \\ x=\frac{-5 \pm \sqrt{5^2-4(1)(5)}}{2(1)} \\ \\ x=\frac{-5 \pm \sqrt{25-20}}{2} \\ \\ x=\frac{-5 \pm \sqrt{5}}{2} \\ \\ \\ Two \ solutions: \\ \\ \boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}$

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Quadratic functions: brainly.com/question/12164750

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8 0

3 years ago

Using the distributive property 7× 1,214

masya89 [10]

The answer is 8,498.

I hope I helped :-)

6 0

3 years ago

Read 2 more answers

Jamel and his sister received a total of $250 for their birthday. If Jamel received $30 less than his sister, how much did each

alexandr402 [8]

Answer:

Jamel - 110 Sister - 140

Step-by-step explanation:

We are going to work backwards. If Jamel received 30 dollars less than his sister, then the total goes down to $220. Then you divide by 2 to split the money between each equally. Now Jamel has $110 and his sister has $110. But you have to add the original $30 back to his sister's total because she got $30 more. Hence Jamel has $110 and his sister has $140.

5 0

3 years ago

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