R= $42 rental cost per day
Mileage= $0.20 per mile
m= number of miles driven
Budget= $98 per day
EQUATION
$98> $0.20m + $42
SOLUTION
$98> $0.20m + $42
subtract 42 from both sides
$56> $0.20m
divide both sides by $0.20
280> m
They have to drive less than 280 miles per day to stay within their $98 budget.
SAME SOLUTION INEQUALITIES
Set up the equations with new numbers, substitute 280 for m and pick another variable to solve for. I chose to solve for total rental cost.
m= 280 miles per day
R= Rental cost per day
R> $0.10(280) + $50
R> $28 + $50
R> $78
Equation #1
$78> $0.10m + $50
----------
m= 280 miles per day
R= Rental cost per day
R> $0.18(280) + $44
R> $50.40 + $44
R> $94.40
Equation #2
$94.40> $0.18m + $44
ANSWER: 280> m; They have to drive less than 280 miles per day to stay within their $98 budget.
Equation #1: $78> $0.10m + $50
Equation #2: $94.40> $0.18m + $44
Hope this helps! :)
The last option because the range is the input values
Answer:

Step-by-step explanation:
figure out 4a(x) and 2b(x) separately by distributing, and then add them together to get your answer.
hope this helps :)
Yes, your answer are correct! There is a little work to be shown on number 1, but it isn't necessary.
Hope this helps! Brainliest it if it does!
We first calculate the percentage increase on the tax
Old value = 25×9 = 225 ⇒ The value 9 represents the 9 lots of thousands of the house's value
New value = 28×9 = 252
Increase in tax = 252 - 225 =27
Percentage increase = (27÷225) ×100 = 12%
The amount of yearly rent would be then increased by 12%
Monthly rent = $60
Yearly rent = 60×12 = $720
Increase by 12% = 720×1.12 = 806.4 ⇒ The value 1.12 is the multiplier, obtained from 100%+12%=112%=1.12
The monthly rent is 806.4÷12 = $67.20 which is an increase of $7.20 per month