Let w represent the width of the rectangle in cm. Then its length in cm is (3w+9). The perimeter is the sum of two lengths and two widths, so is ...
... 418 = 2(w + (3w+9))
... 209 = 4w +9 . . . . . . divide by 2, collect terms
... 200 = 4w . . . . . . . . subtract 9
... 50 = w . . . . . . . . . . divide by 4
... length = 3w+9 = 3·50 +9 = 159
The dimensions of this piece of land are 159 cm by 50 cm.
Answer:
2x^2+16x-66
Step-by-step explanation:
Use FOIL (First, Outside, Inside, Last)
(2x-6)(x+11)
F- 2x*x=2x^2
O-2x*11=22x
I--6*x=-6x
L--6*11=-66
2x^2+22x-6x-66
Combine like terms
2x^2+16x-66
Answer:
Step-by-step explanation:
y = -2x+5
slope of line is -2.
slope of parallel to line is also -2
point-slope equation for line of slope -2 that passes through (-5,3):
y-3 = -2(x+5)
Answer: 24 is the LCD
He is correct.
4 20/24 or 4 5/6 simplified