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Anettt [7]
4 years ago
15

1. A 5 Ohm resistor is connected to a 9 Volt battery. How many Joules of thermal energy are produced in 7 minutes?

Physics
1 answer:
MariettaO [177]4 years ago
5 0

Answer:

Question 1: 189 joules

Question 2: 2.25 watts

Question 3: 405 joules

Question 4: 0.00125 watts

Question 5: 450000 joules

Explanation:

question 1:

Volt=1.5v

Resistance =5 ohms

Time=7 minutes

Time=7 x 60

Time=420 seconds

Current =voltage ➗ resistance

Current =1.5 ➗ 5

Current =0.3 amps

Energy=current x voltage x time

Energy=0.3 x 1.5 x 420

Energy =189 joules

Question 2:

Current =0.5 amps

Voltage =4.5v

Power=current x voltage

Power=0.5 x 4.5

Power=2.25 watts

Question 3:

Current=0.5 amps

Voltage=4.5v

Time =3 minutes

Time =3x60

Time =180 seconds

Energy=current x voltage x time

Energy=0.5 x 4.5 x 180

Energy =405 joules

Question 4:

Resistance=50 ohms

Current =5 milliamps

Current =5/1000

Current =0.005 amps

Power =current x current x resistance

Power=0.005 x 0.005 x 50

Power=0.00125 watts

Question 5:

Power =50 watts

Time=2.5 hour

Time=2.5 x 60 x 60

Time =9000 seconds

Energy=power x time

Energy=50x9000

Energy=450000 joules

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Answer + Explanation:

B

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A car is traveling at 120 km/h (75 mph). When applied the braking system can stop the car with a deceleration rate of 9.0 m/s2.
Bumek [7]

Answer:

the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

Explanation:

Given that;

speed of car V  = 120 km/h = 33.3333 m/s

Reaction time of an alert driver = 0.8 sec

Reaction time of an alert driver = 3 sec

extra time taken by sleepy driver over an alert driver = 3 - 0.8 = 2.2 sec

now, extra distance that car will travel in case of sleepy driver  will be'

S_d = V × 2.2 sec

S_d = 33.3333 m/s × 2.2 sec

S_d = 73.3333 m

hence, number of car of additional car length  n will be;

n = S_n / car length

n = 73.3333 m / 5m

n = 14.666 ≈ 15

Therefore, the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

8 0
4 years ago
How many joules of heat are needed to raise the temperature of 50.0 g of aluminum from 10°C to 110°C, if the specific heat of al
dusya [7]

Answer:

Heat required to raise the temperature of the aluminium is 4750 J

Explanation:

As we know that the heat energy required to raise the temperature of the aluminium is given as

Q = ms\Delta T

here we know that

m = 50 g

\Delta T = 110 - 10

\Delta T = 100 ^oC

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Q = 50(0.95)(100)

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5 0
4 years ago
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Answer:

D) equal to the flux of electric field through the Gaussian surface B.

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4 years ago
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