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Daniel [21]
3 years ago
9

Help needed for science homework

Physics
1 answer:
Gemiola [76]3 years ago
8 0
The answer is 1/2 * base * height
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Compare the three types of friction
Dominik [7]
The what i don't understand lol
5 0
4 years ago
I walk 500 meters due east from my home and then walk 866
mars1129 [50]

The magnitude of the total displacement is 1000 m

Explanation:

Displacement is a vector quantity connecting the initial position and final position of motion of an object.

The magnitude of the displacement is therefore the distance in a straight line between the initial and final position of motion.

The person in the problem has the following motions:

500 meters due east

866 meters due north

The two motions are perpendicular to each other, so they form the sides of a right triangle, of which the hypothenuse corresponds to the magnitude of the total displacement.

Therefore, the magnitude of the displacement can be simply found by using Pythagorean's theorem:

d=\sqrt{d_x^2+d_y^2}=\sqrt{500^2+866^2}=1000 m

Learn more about distance and displacement:

brainly.com/question/3969582

#LearnwithBrainly

4 0
4 years ago
For a object to be in projectile motion, what force must be acting on it
ArbitrLikvidat [17]

Answer:

Explanation:

gravity

A projectile is an object upon which the only force is gravity. Gravity acts to influence the vertical motion of the projectile, thus causing a vertical acceleration. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity.

5 0
3 years ago
I NEED HELP ASAP!!!!!
Annette [7]

Answer:

1. S = d/t S = speed D = distance traveled T= time elapsed

Explanation:

i can answer more in a minute sorry!!

5 0
3 years ago
1. A satellite (mass = 4.44 x 109 kg) travels in orbit around the Earth at a distance of 1.9 x 10'm above
Nuetrik [128]

Answer:

The force of gravitational attraction between the satellite and Earth is 2.587\times 10^{10} newtons.

Explanation:

Statement is incorrect. Correct statement is:

<em>A satellite (</em>m = 4.44\times 10^{9}\,kg<em>) travels in orbit around the Earth at a distance of </em>1.9\times 10^{6}\,m<em> above Earth's surface. What is the force of gravitational attraction between the satellite and Earth?</em>

The gravitational force experimented by the satellite (F), in newtons, is calculated by Newton's Law of Gravitation, whose equation is defined by following formula:

F = \frac{G\cdot m \cdot M}{R^{2}} (1)

Where:

G - Gravitational constant, in cubic meters per kilogram-square second.

m - Mass of the satellite, in kilograms.

M - Mass of the Earth, in kilograms.

R - Distance of the satellite with respect to the center of the Earth, measured in meters.

If we know that G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}, m = 4.44\times 10^{9}\,kg, M = 5.972\times 10^{24}\,kg and R = 8.271\times 10^{6}\,m, then the force of gravitational attraction between the satellite and Earth is:

F = 2.587\times 10^{10}\,N

The force of gravitational attraction between the satellite and Earth is 2.587\times 10^{10} newtons.

6 0
3 years ago
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