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zysi [14]
2 years ago
15

Which is the correct standard notation for 9.3x10^5

Physics
1 answer:
horsena [70]2 years ago
7 0

Explanation:

9.3x105

Simplifies to:

9.3x100000

=9.3x100000  

Hope that helps

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A traveling electromagnetic wave in a vacuum has an electric field amplitude of 98.9 V/m . Calculate the intensity ???? of this
Pani-rosa [81]

Answer:

intensity = 12.98 W/m^2

Energy = 3.93 J

Explanation:

As we know that the magnitude of electric field intensity is given as

E = 98.9 V/m

now we know that intensity of the wave is given as the product of energy density and speed of the wave

intensity = \frac{1}{2}\epsilon_0 E^2 c

intensity = \frac{1}{2}(8.85 \times 10^{-12})(98.9)^2(3\times 10^8)

intensity = 12.98 W/m^2

so intensity is the energy flow per unit area per unit of time

so the energy that flows through the area of 0.0259 m^2 in 11.7 s is given as

Energy = Area \times time \times intensity

Energy = 0.0259(11.7)(12.98)

Energy = 3.93 J

7 0
3 years ago
A 50-kg cart is on an incline of 30 degrees above the horizontal. The cart is at rest. The static coefficient of the slope is 0.
sesenic [268]

The cart is at rest, so it is in equilibrium and there is no net force acting on it. The only forces acting on the cart are its weight (magnitude <em>w</em>), the normal force (mag. <em>n</em>), and the friction force (maximum mag. <em>f</em> ).

In the horizontal direction, we have

<em>n</em> cos(120º) + <em>f</em> cos(30º) = 0

-1/2 <em>n</em> + √3/2 <em>f</em> = 0

<em>n</em> = √3 <em>f</em>

and in the vertical,

<em>n</em> sin(120º) + <em>f</em> sin(30º) + (-<em>w</em>) = 0

<em>n</em> sin(120º) + <em>f</em> sin(30º) = (50 kg) (9.80 m/s²)

√3/2 <em>n</em> + 1/2 <em>f</em> = 490 N

Substitute <em>n</em> = √3 <em>f</em> and solve for <em>f</em> :

√3/2 (√3 <em>f </em>) + 1/2 <em>f</em> = 490 N

2 <em>f</em> = 490 N

<em>f</em> = 245 N

(pointed up the incline)

4 0
3 years ago
Which of the following is described here? "Point your skis straight down the fall line with your skis parallel and about a foot
elena55 [62]

answer d. down hill schussing

Explanation:

I took the quiz

3 0
3 years ago
Read 2 more answers
At a particular instant, a proton at the origin has velocity &lt; 5e4, -2e4, 0&gt; m/s. You need to calculate the magnetic field
vesna_86 [32]

Answer:

9.7\times 10^{-5} T

Explanation:

Velocity =5\times 10^4i-2\times 10^4j

r=0.03i+0.05j

r=\mid r\mid=\sqrt{(0.03)^2+(0.05)^2}=0.058

v=\mid V\mid=\sqrt{(5\times 10^4)^2+(-2\times 10^{4})^2}=5.39\times 10^{2}

We know that

B=\frac{mv}{qr}

Where q=1.6\times 10^{-19} C

Mass of proton=1.67\times 10^{-27} kg

Using the formula

B=\frac{1.67\times 10^{-27}\times 5.39\times 10^2}{1.6\times 10^{-19}\times 0.058}

B=9.7\times 10^{-5} T

3 0
3 years ago
What evidence would you observe if the law of conservation of mass is obeyed when mixing two solutions?​
Marianna [84]

Answer:

You should have noticed that the number of atoms in the reactants is the same as the number of atoms in the product. The number of atoms is conserved during the reaction. However, you will also see that the number of molecules in the reactants and products are not the same.

3 0
3 years ago
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