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Zolol [24]
3 years ago
14

Factorising quadratics 2nd page

Mathematics
1 answer:
mihalych1998 [28]3 years ago
7 0
A^2-b^2=(a+b)(a-b)

1: x^2-4=(x+2)(x-2)
2: (x+8)(x-8)
3: (x+10)(x-10)
4: (x+14)(x-14)
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For the equation below, determine its order. Name the independent variable, the dependent variable, and any parameters in the eq
PIT_PIT [208]

Answer:

The equation is an differential equation of second order.

The dependent variable is x, while t is the independent variable.

Step-by-step explanation:

The order of the equation depends on the greatest grade of the derivative, in this case it's the second derivative (x'')

Since x is a function of t, we would have that t is the independent variable while x is the dependent variable.

3 0
3 years ago
Choose the equation that models the following statement: The current, I amps, produced by a battery is inversely proportional to
Anika [276]
By definition we have to:
 V = I * R
 Where,
 V: Voltage.
 I: Current.
 R: Resistance.
 The current, I amps, produced by a battery is inversely proportional to the resistance, R ohms. Clearing I have:
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 rewriting:
 I = V * (1 / R)
 answer:
 The equation that models the statement is:
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7 0
3 years ago
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Solve and simplify, typing the final answer as a fraction 1/4 ÷ 3/8
natita [175]

[ Answer ]

2 / 3


[ Explanation ]


1 * 8 / 4 * 3


8 / 12


Simplify:

2 / 3


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6 0
3 years ago
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A road perpendicular to a highway leads to a farmhouse located d miles away. An automobile traveling on this highway passes thro
pshichka [43]

Answer:

\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}

Step-by-step explanation:

A road is perpendicular to a highway leading to a farmhouse d miles away.

An automobile passes through the point of intersection with a constant speed \frac{dx}{dt} = r mph

Let x be the distance of automobile from the point of intersection and distance between the automobile and farmhouse is 'h' miles.

Then by Pythagoras theorem,

h² = d² + x²

By taking derivative on both the sides of the equation,

(2h)\frac{dh}{dt}=(2x)\frac{dx}{dt}

(h)\frac{dh}{dt}=(x)\frac{dx}{dt}

(h)\frac{dh}{dt}=rx

\frac{dh}{dt}=\frac{rx}{h}

When automobile is 30 miles past the intersection,

For x = 30

\frac{dh}{dt}=\frac{30r}{h}

Since h=\sqrt{d^{2}+(30)^{2}}

Therefore,

\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+(30)^{2}}}

\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}

3 0
3 years ago
Use x=5, equals, 5 to identify the value of each expression.
Lesechka [4]

Answer:

The answer to the first question is 625

The answer to the second question is 1

The answer to the third question is 1

4 0
3 years ago
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