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Mazyrski [523]
3 years ago
13

William gave 4 football cards to each

Mathematics
1 answer:
andreev551 [17]3 years ago
4 0

Answer:

Cannot be determined

Step-by-step explanation:

There is not enough information to solve this question. You would need to know how many friends he has in order to solve this.

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10. A garden 150 m long and 80 m wide has a road 2 m wide all around
Sergio [31]

Answer:

<em>length</em><em> </em><em>l</em><em> </em><em>=</em><em>150</em><em> </em>

<em>breadth</em><em> </em><em>b</em><em> </em><em>=</em><em> </em><em>80</em><em> </em>

<em>lf</em><em> </em><em>2</em><em> </em><em>m</em><em> </em><em>wide</em><em> </em><em> </em><em>of</em><em> </em><em>road</em><em> </em><em>is</em><em> </em><em>inside</em><em> </em><em>the</em><em> </em><em>garden</em>

<em>then</em>

<em>lt's</em><em> </em><em>area</em><em> </em><em>=</em><em> </em><em>l</em><em> </em><em>×</em><em>b</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>150</em><em> </em><em>×</em><em> </em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>300m</em><em>^</em><em>2</em>

6 0
3 years ago
Need help due in 25 minutes
masha68 [24]

Answer:

Area = 400  Perimeter = 80

Step-by-step explanation:

aree = 400

side = sqrt of 400 = 20

perimeter = 4*20 = 80

7 0
3 years ago
The ratio in simplest form
Hoochie [10]
It’s already in it’s simplest form!
8 0
3 years ago
Helpppppppppppppppp me plzzzzzzzzzzzzzz
murzikaleks [220]
Your answer is correct, your on the right track as well. Just flip the negative number to its respective location. 

Good luck :)
8 0
3 years ago
Verify that the Intermediate Value Theorem applies to the indicated interval and find the value of c guaranteed by the theorem.
Molodets [167]

Answer:

See verification below

Step-by-step explanation:

Remember that the Intermediate Value Theorem (IVT) states that if f is a continuous function on [a,b] and f(a)<M<f(b), there exists some c∈[a,b] such that f(c)=M.

Now, to apply the theorem, we have that f(0)=0²+0-1=-1, f(5)=5²+5-1=29, then f(0)=-1<11<29=f(5). Additionally, f is continous since it is a polynomial. Then the IVT applies, and such c exists.

To find, c, solve the quadratic equation f(c)=11. This equation is c²+c-1=11. Rearranging, c²+c-12=0. Factor the expression to get (c+4)(c-3)=0. Then c=-4 or c=3. -4 is not in the interval, then we take c=3. Indeed, f(3)=3²+3-1=9+3-1=11.

5 0
3 years ago
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