Answer:
4!
Step-by-step explanation:
The answer is not 8, its 4. Just took the test!
If we take the value of t to be 15 and then we perform the calculations of 2 times t divided by 3, we can express it all by two equations substituting the value given for t like so:
t = 15
2t/3 = 2(15)/3 = 30/3 = 10
The maxima of f(x) occur at its critical points, where f '(x) is zero or undefined. We're given f '(x) is continuous, so we only care about the first case. Looking at the plot, we see that f '(x) = 0 when x = -4, x = 0, and x = 5.
Notice that f '(x) ≥ 0 for all x in the interval [0, 5]. This means f(x) is strictly increasing, and so the absolute maximum of f(x) over [0, 5] occurs at x = 5.
By the fundamental theorem of calculus,

The definite integral corresponds to the area of a trapezoid with height 2 and "bases" of length 5 and 2, so


X= base
Area= 1/2(base)(height)
24=1/2(b)(4)
24=(4*1*b)/2
24=4b/2
Divide 2 into 4
24=2b
Divide both sides by 2
12=b
base= x= 12 units
Hope this helps! :)