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ra1l [238]
3 years ago
11

Help with this please!!!!!

Mathematics
1 answer:
Vlad [161]3 years ago
6 0
Gh is a half of DF because it is a midline
2(3x-4)=9x-59
6x-8=9x-59
3x=51
X=17
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If someone has a cube shaped box that measures 9 inches along each edge. Can they fit 1,000 1 square inch cubes inside the box
Stolb23 [73]

Answer:

The area of the box is equal to 9^3 = 729 in^3

729<1000  


Step-by-step explanation:

No since the volume of the box is less than the total volume of the cubes

4 0
3 years ago
How do you solve <br> 69-3a=0
aleksandrvk [35]
69 - 3a = 0

69 - 3a (-69) = 0 (-69)

-3a = -69

-3a(/-3) = -69(/-3)

a = 23

hope this helps
8 0
3 years ago
Given a standard deck of 52 cards, 3 cards are dealt without replacement. Using this situation, answer the questions below.&lt;b
kherson [118]
Given that <span>3 cards are dealt without replacement in a </span><span>standard deck of 52 cards.

Part A:

There are 4 queens in a standard deck of 52 card, thus the probability that the first card is a queen is given by 4 / 52 = 1 / 13.

Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given</span> by 3 / 51 = 1 / 17

Similarly the probability that the third card is a queen is given by 2 / 50 = 1 / 25.

Therefore, the probability that <span>all three cards are queens is given by

\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} = \frac{1}{5525}



Part B:

Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.



Part C:

Given that the first card is a queen, then there are 3 queens remaining out of 51 cards remaining, thus the number of cards that are not queen is 51 - 3 = 48 cards.

Therefore, </span>if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17



Part D:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.

Therefore, </span>if two of the three cards are queens ,<span>the probability that you will be dealt three queens</span> is given by 2 / 50 = 1 / 25 = 0.04



Part E:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining, thus the number of cards that are not queen is 50 - 2 = 48 cards.

Therefore, </span>if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96
8 0
3 years ago
Solve the sequence:0,5,12,23,34____​
MrRissso [65]

Step-by-step explanation:

the answer is 49

I may not be correct

4 0
2 years ago
Help me please with math​
Nady [450]
Answer: There is no question

Can you please show the question?
5 0
2 years ago
Read 2 more answers
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