All categories

3 years ago

Solve the proportion below. 5/x = 30/72 a.12 b.9 c.6 d.30

Mathematics

2 answers:

AnnyKZ [126]3 years ago

3 0

Answer:

A. 12

Step-by-step explanation:

Cross multiply:

30x = 72(5)

x = 360/30

x = 12

Stels [109]3 years ago

3 0

Hey there! :)

Answer:

x = 12.

Step-by-step explanation:

Set the two proportions equal to each other:

$\frac{5}{x} = \frac{30}{72}$

Cross multiply to solve for x:

5 · 72 = 30 · x

360 = 30x

Divide both sides by 30:

360/30 = 30x/30

12 = x.

Therefore, the value of 'x' in this proportion is 12.

You might be interested in

Which answer describes the transformation of f(x)=x2−1 to g(x)=(x−1)2−1 ?

artcher [175]

A vertical translation 1 unit down since for example x is 1, if u plug it in both equations it is f(1)=1*2-1 which equals f(1)=1 and the point is (1,1) for the other one, g(1)=(1-1)2-1 it equals g(1)=-1

4 0

3 years ago

Read 2 more answers

What is 100 in exponential form?

Thepotemich [5.8K]

10 • 10=
Is 10^2
In exponential form

3 0

3 years ago

P and W are twice-differentiable functions with P(7)=2(W(7)). The line y=9+2.5(x-7) is tangent to the graph of P at x=7. The lin

fiasKO [112]

Using the product rule, we have

$m(x) = x W(x) \implies m'(x) = xW'(x) + W(x)$

so that

$m'(7) = 7W'(7) + W(7)$

The equation of the tangent line to W(x) at x = 7 has all the information we need to determine m' (7).

When x = 7, the tangent line intersects with the graph of W(x), and

y = 4.5 + 2 (7 - 7) ==> y = 4.5

means that this intersection occurs at the point (7, 4.5), and this in turn means W (7) = 4.5.

The slope of this tangent line is 2, so W' (7) = 2.

Then

$m'(7) = 7\cdot2 + 4.5 = \boxed{18.5}$

4 0

2 years ago

Please help I don't get this one

Semenov [28]

Its A you just have to count the lines and say the numbers 1-4

7 0

3 years ago

Ericka decided to compare her observation to the average annual trend, which shows the water rising 1.8 mm/year. Remember, she u

Alex787 [66]

Answer with explanation:

Presume that, initial water level to be, 0 mm, at a time t=0.

And water level is rising at the rate of $1.8 \frac{\text{mm}}{\text{year}}$ .

After 6.2 years level of water will be =1.8 × 6.2

=11.16 mm

→Averge, that is increase in water level after 6.2 years is given by

$=\frac{W_{2}-W_{1}}{t_{2}-t_{1}}\\\\=\frac{11.16-0}{6.2-0}\\\\=\frac{11.16}{6.2}\\\\=1.8 \frac{\text{mm}}{\text{year}}$

→→Rate of Depreciating of water level is given by = Negative of Increase of water level= $-1.8 \frac{\text{mm}}{\text{year}}$

5 0

3 years ago

Read 2 more answers