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3 years ago

Rule:start at 3 1/8 subtract 3/4

Mathematics

1 answer:

SSSSS [86.1K]3 years ago

6 0

Answer:

2 3/8

Step-by-step explanation:

If what you're saying it 3 1/8 - 3/4 then...

3 1/8 - 3/4

3 1/8 - 6/8

25/8 - 6/8

19/8

2 3/8

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Given f(x) = 3x + 1, solve for x when f(x) = 7.

irakobra [83]

Answer:

f(7) = 22 or x =2

Step-by-step explanation:

f(x) = 3x + 1
f(7) = 3(7) + 1
f(7) = 21 + 1
f(7) = 22

<u>Or if the equation meant it like this:</u>

f(x) = 3x + 1
7 = 3x + 1
6 = 3x
2 = x

4 0

3 years ago

Read 2 more answers

Express as -80/112 as a rational: numerator = -5

Anastasy [175]

Answer:

-80\112 = -5\7

we divided both numbers by 16

8 0

3 years ago

F(x) = 4x-5; f(-2)<br> please help

Firdavs [7]

Answer:

f(x)=-13

Step-by-step explanation:

Substitute x with -2

4 times -2 is -8

-8-5 is -13

Thus f(x)=-13

Hope this helps!

5 0

3 years ago

Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calcul

sesenic [268]

The expression $5 = \sqrt{(x-6^2)+(y - 5)^2}$ can be used to find the coordinate of Point B. Option C is correct.

Given that,
Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calculate the coordinates for point B is to be determined.

<h3>What is the equation?</h3>

The equation is the relationship between variables and represented as y = ax +c is an example of a polynomial equation.

Let the coordinates of B be (x, y)
Now the distance between A (6, 5) and B (x, y) is c = 5 units
So, by the distance formula, the distance between two points is given as,

$C = \sqrt{(x_1-x_2)^2 +(y_1-y_2)^2}$

now put the value in the formula.

$5 = \sqrt{(x-6^2)+(y - 5)^2}$

Thus, expression $5 = \sqrt{(x-6^2)+(y - 5)^2}$ can be used to find the coordinate of Point B. Option C is correct.

Learn more about equation here:

brainly.com/question/10413253

#SPJ1

4 0

1 year ago

A circle has a center of (5,-5) and goes through (6,-2). What is the radius?

Fittoniya [83]

Start with the equation of a circle whose center is at (h,k) and whose radius is r:

(x-h)^2 + (y-k)^2 = r^2

Substituting the given coordinates of the center:

(x-5)^2 + (y-[-5])^2 = r^2, or (x-5)^2 + (y+5)^2 = r^2

Substituding the given coordinates of a point (6,-2) on the circle:

(6-5)^2 + (-2+5)^2 = r^2

Simplifying:

1^2 + 3^2 = r^2, or 1 + 9 = r^2, or 10= r^2. Then r = sqrt(10).

6 0

3 years ago