Answer:
Period =½
Equation of midline, y=0
Maximum =2
Minimum=-2
Step-by-step explanation:
The given function is
The period is given by:
The equation of the midline is y=0 since there is no vertical shift
The amplitude of this function is 2 so the range is -2≤y≤2.
Hence the maximum value is 2 and minimum value is -2
Answer:
Any [a,b] that does NOT include the x-value 3 in it.
Either an [a,b] entirely to the left of 3, or
an [a,b] entirely to the right of 3
Step-by-step explanation:
The intermediate value theorem requires for the function for which the intermediate value is calculated, to be continuous in a closed interval [a,b]. Therefore, for the graph of the function shown in your problem, the intermediate value theorem will apply as long as the interval [a,b] does NOT contain "3", which is the x-value where the function shows a discontinuity.
Then any [a,b] entirely to the left of 3 (that is any [a,b] where b < 3; or on the other hand any [a,b] completely to the right of 3 (that is any [a,b} where a > 3, will be fine for the intermediate value theorem to apply.
Answer:
10
Step-by-step explanation:
Shifting a circle results to changes in the coordinates of the circle. For instance, if the coordinates of the center of the circle is taken to be (0,0), the new coordinates will be [(0+5),(0+2)] after shifting. The equation of the circle will also change with the same margin.
That is, the new equation will be;
(5+x)^2+(2+y)^2 =19
Notice, only the coordinates changes.
