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2 years ago

X2-3x-4=0 please help me factorize

2 answers:

4 0

X² - 3x - 4 = 0

Reverse FOIL method . . .

(x - 4)(x + 1) = 0

one of the paranthesis has to be equal to zero if the other is not . . .

x - 4 = 0

x = 4

x + 1 = 0

x = -1

EastWind [94]2 years ago

3 0

$x^2-3x-4=0\\\\x^2-3x-4=\\x^2+x-4x-4=\\x(x+1)-4(x+1)=\\(x+1)(x-4)\\\\(x+1)(x-4)=0,\ when:\\\\x+1=0\ \ \ \ \ \ \ \ or\ \ \ \ \ \ \ x-4=0\\x=-1\ \ \ \ \ \ \ \ \ \ \ or\ \ \ \ \ \ \ x=4$

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3 years ago

Express sin A,cos A and tan A as ratios

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Answer:

Part A) $sin(A)=\frac{2\sqrt{42}}{23}$

Part B) $cos(A)=\frac{19}{23}$

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Step-by-step explanation:

Part A) we know that

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2 years ago

Please help me! I don’t understand

Sedaia [141]

Answer:

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2 years ago

Directions - For the following problem, write a paragraph proof to justify each step you make. All work must be neat,

nlexa [21]

$$ PS = \frac{4}{3} x$

Solution:

Given PRQ is a triangle.

ST is a line parallel to RQ.

$$PT = x, \ PQ = 3x, \ SR=\frac{8}{3}x$

$TQ=PQ-PT$

$TQ=3x -x=2x$

Triangle proportionality theorem,

If a line parallel to one side of a triangle intersects the other two sides, then it divides the two sides proportionally.

$$\frac{PS}{SR} =\frac{PT}{TQ}$

$$\frac{PS}{\frac{8}{3} x} =\frac{x}{2x}$

Do cross multiplication, we get

$$ PS \times 2x=x \times \frac{8}{3} x$

Divide by 2x on both sides, we get

$$ PS = \frac{4}{3} x$

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2 years ago

Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. 2x-y=

Bond [772]

Answer:

The system of linear equations has infinitely many solutions

Step-by-step explanation:

Let's modified the equations and find the answer.

Using the first equation:

$2x-y=5$ we can multiply by 2 in both sides, obtaining:

$2*(2x-y)=2*5$ which can by simplified as:

$4x-2y=10$ which is equal to:

$4x=2y+10$

Considering the second equation:

$=4x+ky=2$

Taking into account that from the first equation we know that: $4x=2y+10$ , we can express the second equation as:

$2y+10+ky=2$ , which can be simplified as:

$(2+k)y=2-10$

$(2+k)y=-8$

$y=-8/(2+k)$

Because (-8) is being divided by (2+k), then (2+k) can't be equal to 0, so:

$2+k=0$ if $k=-2$

This means that k can be any number different than -2, and for each of these solutions, there is a different solution for y, allowing also, different solutions for x.

For example, if k=0 then

$y=-8/(2+0)$ which give us y=-4, and, because:

$4x=2y+10$ if y=-4 then $x=(-8+10)/4=0.5$

Now let's try with k=-1, then:

$y=-8/(2-1)$ which give us y=-8, and, because:

$4x=2y+10$ if y=-8 then $x=(-16+10)/4=-1.5$ .

Then, the system of linear equations has infinitely many solutions

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3 years ago