<span>The equation is e = 300 - 10t. t is greater or equal than 0 and given that e cannot be negative, 300 - 10 t greaetr or equal than 0 => 10 t greater or equal than 300, and t greater or equal than 300/10 = 30. This is the viable points are times from 0 to 10 and elevation from 300 to 0. Some points are (0,300) which is the initial point (when Rory is on the top); (1, 290); (2, 280); (3, 270); (4, 260); (5, 250); (6, 240); (10, 200), (20, 100), (30, 0).</span>
Answer:
The box-and-whisker plot for the given question is as shown at the attached figure.
Minimum = 11
Lower quartile = Q1 = 12
Median = Q2 = 23.5
Upper quartile = Q3 = 27
Maximum = 33
<u>So, according to the given data and the figure:</u>
- The box will go from <u>12 to 27</u> ⇒ Q1 to Q3
- A line dividing the box will go at <u>23.5</u> ⇒ Q2
- The left whisker will go from <u>11 to 12</u> ⇒ Minimum to Q1
- The right whisker will go from to <u>27 to 33</u> ⇒ Q2 to Maximum
<h2>If you mean :</h2>
Inverse both sides
Multiply both sides by 4
Divide both sides by 3
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<h2>If u mean : </h2>
Multiply both sides by the 3
Divide both sides by 4
Y+4=-36
y=-40
Have a great day :)