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2 years ago

Is 2, 4, and 5 right

Mathematics

1 answer:

hram777 [196]2 years ago

6 0

4 and 5 are right, but 2 isn't because consonants are the opposite of vowels. So, you wouldn't use a or e.

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If a = √3-√11 and b = 1 /a, then find a² - b²

Serga [27]

If $b=\frac1a$ , then by rationalizing the denominator we can rewrite

$b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8$

Now,

$a^2 - b^2 = (a-b) (a+b)$

and

$a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8$

$a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8$

$\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}$

5 0

1 year ago

2-^3= -8 -6 -1/6 1/8 2/3

Allisa [31]

Answer:

-8

Step-by-step explanation:

Hope this helps!

8 0

3 years ago

Help please I need this ASAP!!!!!!!!!!!!!!!!!!!!!!

CaHeK987 [17]

Answer:

Step-by-step explanation:

the missing degree is a multiple of 360, so 0.

graph is like squiggly touching -1 at pi and touching 1 at 2 pi and so forth

3 0

2 years ago

2(3x-5)<4x+6 as a word problem

Nastasia [14]

Answer: x<8

Step-by-step explanation:

3 0

3 years ago

Simplify (dont mind me just need charactrrs)

siniylev [52]

That is also equal to (9÷1)÷3, so it will be the same as 9÷3. Therefore, the answer is 3.

6 0

3 years ago

Read 2 more answers