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lions [1.4K]
3 years ago
11

SIMILAR SHAPE QUESTION. Please answer!!

Mathematics
1 answer:
natita [175]3 years ago
4 0
X = 4 cm


the area of trapezium is

A = (4)(6) + (1/2)(4)(9-6)
A =30 cm^2

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4 0
3 years ago
Given: y=x^2-4x-12
sergeinik [125]

Answer:

see below

Step-by-step explanation:

y=x^2-4x-12

Set equal to 0 to find the zeros

0 =x^2-4x-12

Factor.  What 2 numbers multiply to -12 and add to -4

-6*2 = -12  

-6+2 = -4

0= (x-6) (x+2)

Using the zero product property

0=x-6         0 = x+2

x=6            x = -2

zeros: -2,6

Vertex

h = -b/2a = - (-4)/ 2(1) = 4/2 = 2

OR  Average the roots  (-2+6)/2 = 4/2 =2

The y coordinate is found by substituting into the equation

y = (2)^2 -4(2) -12

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y =-16

vertex : (2, -16)

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3 years ago
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Please?
just olya [345]

Answer:

the answer is 12

Step-by-step explanation:

idk

8 0
3 years ago
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