Answer:
12
Step-by-step explanation:
No. of red flyers = 6
No. of blue flyers = 4
We need to find the minimum number of flyers of each color if she gave out the same number of red and blue flyers. For this we must find the LCM of 6 and 4.
Prime factorization of 6 = 2×3
Prime factorization of 4 = 2×2
Lowest common multiple of 6 and 4 = 12
Hence, there are 12 minimum number of flyers of each color
Okay. What I know so far is that the integers will all be negative. We don't have to count too high to do this. So for this, it's like pick any four numbers. Or you could divide 18 by half and find the addition problems that you know would equal 9. What I see is that -3 + -4 + -5 + -6 = -18. There are all four consecutive integers. The trend is that you can draw a line tracing to the number of the opposite side of the question and you can see they each equal nine. Most people would be tricked and say 6, because they ignore the negative symbol, but here's the catch. The lower the number in front of the negative sign, the greater it is. So in this case, the lowest number in front of the negative symbol is 3, which would also mean that -3 is the highest when it comes to all of these numbers. So -3 is the greatest out of the four consecutive integers.
Answer:
C
Step-by-step explanation:
12x + 9 = 13x + 1
9-1 = 13x - 12x
8 = x
Answer:
166.66 and 166.67 rounded
Step-by-step explanation:
Step-by-step explanation:
If we count for both numbers up to 36, we start seeing a pattern...
Candy: 6 12 18 24 30 36
Danny: 4 8 12 16 20 24 28 32 36
Every other number in Candy's counting is also counted by Danny. So here's what we'll do:
600/6 = 100
This is how many numbers Candy counted overall.
100/2 = 50
This is how many numbers Danny counted that were also numbers Candy counted.
Answer:
50 of the numbers that candy counted were also counted by Danny.
