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Alekssandra [29.7K]
3 years ago
8

A company makes cars at two factories. Some of the cars need repairs in the first year and some do not. This two-way frequency t

able shows the proportion of cars at each factory that need repairs or do not need repairs in the first year. Need repairs in first year Do not need repairs in first year Factory A 0.05 0.95 Factory B 0.02 0.98
Mathematics
1 answer:
Lerok [7]3 years ago
4 0
From the four answers two are correct.
A. Compared to Factory A, B has a larger percentage of cars that do not need repairs.
B. Among cars from factory A, a larger percentage of cars do not need repairs than do need repairs in the first year
Both of these answers are indeed correct.
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A population of rabbits in a lab, p(x), can be modeled by the function p(x) = 20(1.014)x , where x represents the number of days
Nitella [24]

Answer:

20 = initial population of the rabbits

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the average rate of change from day 50 to day 100 is 0.8

Step-by-step explanation:

A population of rabbits in a lab, p(x), can be modeled by the function

p(x) = 20(1.014)^x

This model is exponential. Where 20 = initial population of the rabbits

1.014 = growth rate of the rabbits with 1.4% increase rate of the rabbits

To find the average rate of change from day 50 to day 100,

find the population p(50) and p(100). Subtract them and divide by 100 - 50 = 50. 

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The rate of change is 0.8. 

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