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rewona [7]
3 years ago
6

Carl’s new car get 27 miles per gallon. What is the equation that represents y, the total miles driven on x gallons of gas?

Mathematics
2 answers:
Olenka [21]3 years ago
6 0
Answer:

Y = 27x

Explanation:

Carl can go 27 miles for every mile in this case, x has the value of the total gallons used
scoray [572]3 years ago
3 0
The answer to your question is Y=27x.
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Help please!!!!!!!!!
Triss [41]
The answer is -4, hope this helped
8 0
3 years ago
X/5=2/3=5/y<br><br> 2/3 <br> 4/9<br> 1
Mademuasel [1]
\frac{x}{5}= \frac{2}{3}  = \frac{5}{y}
Break the equation into parts;
\frac{x}{5} = \frac{2}{3} ;  \frac{2}{3}= \frac{5}{y}
Solving for x;
\frac{x}{5} = \frac{2}{3}
x=\frac{10}{3}
Solving for y;
\frac{2}{3} = \frac{5}{y} &#10;y= \frac{3*5}{2} &#10;y= \frac{15}{2}
\frac{x}{y} = \frac{10/3}{15/2}
\frac{x}{y} = \frac{4}{15}
5 0
3 years ago
6 Goes Into 2,000 How Many Times?
Leya [2.2K]

Answer:

333.333

Step-by-step explanation:

2000 devided by 6=333.333

8 0
3 years ago
Medicare would like to test the hypothesis that the average monthly rate for one-bedroom assisted-living facility is equal to $3
aliina [53]

Answer:

C) more than the absolute value of the critical value, we can conclude that the average monthly rate for an assisted-living facility is not equal to $3,300.

Step-by-step explanation:

Hello!

Interest hypothesizes is " the average monthly rate for one-bedroom assisted-living facility is equal to $3300" symbolically: μ = 3300

The study variable is:

X: Monthly rate for a one-bedroom assisted-living facility.

Since there is no information about the distribution of the variable, to be able to study the population mean, I'll assume that the variable has a normal distribution.

The hypothesis is:

H₀: μ = 3300

H₁: μ ≠ 3300

α: 0.05

The statistic to use, considering that there is no known population information and the sample size, is a Student t:

t= <u> X[bar] - μ </u> ~t_{n-1}

       S/√n

n= 12

X[bar]= $3690

S= $530

Using the sample data, calculate the statistic value:

t= <u> 3690 - 3300 </u> = 2.549

       530/√12

The rejection region for this test is two-tailed, with critical values:

t_{n-1; \alpha /2} = t_{11; 0.025} = -2.201

t_{n-1;1-\alpha /2} = t_{11; 0.975} = 2.201

The decision rule is:

Reject the null hypothesis if t ≤ -2.201 or if t ≥ 2.201

Not reject the null hypothesis if -2.201 < t < 2.201

Since the calculated value (2.549) is greater than the right critical value (2.201) the decision is to reject the null hypothesis.

With a signification level of 5%, there is enough evidence to reject the null hypothesis. This means that the population mean of the monthly rate for a one-bedroom assisted living facility is different from $3300.

I hope it helps!

7 0
3 years ago
Find all real numbers on the interval [0.2 t) that satisfy the equation. Use radian measure.
sergejj [24]

Answer:

  x ∈ {2π/3, π, 4π/3} ≈ {2.09440, 3.14159, 4.18879}

Step-by-step explanation:

The equation can be put into standard form by adding 1:

  2cos²(x) +3cos(x) +1 = 0

  (2cos(x) +1)(cos(x) +1) = 0

Values of cos(x) that make this true* are ...

  cos(x) = -1/2 . . . . . . . . . true for x=2π/3, x=4π/3

  cos(x) = -1 . . . . . . . . . . . true for x=π

__

A graphing calculator can be helpful here, too.

_____

* from your knowledge of the short table of trig functions and their signs in different quadrants

3 0
3 years ago
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