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myrzilka [38]
4 years ago
9

X/5=2/3=5/y 2/3 4/9 1

Mathematics
1 answer:
Mademuasel [1]4 years ago
5 0
\frac{x}{5}= \frac{2}{3}  = \frac{5}{y}
Break the equation into parts;
\frac{x}{5} = \frac{2}{3} ;  \frac{2}{3}= \frac{5}{y}
Solving for x;
\frac{x}{5} = \frac{2}{3}
x=\frac{10}{3}
Solving for y;
\frac{2}{3} = \frac{5}{y} 
y= \frac{3*5}{2} 
y= \frac{15}{2}
\frac{x}{y} = \frac{10/3}{15/2}
\frac{x}{y} = \frac{4}{15}
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3 years ago
Determine if y = 2x + 1 is a function
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4 years ago
Solve the simultaneous linear equation 2x+5y=11, 7x+4y=2​
Andrews [41]

Answer:

x = -\frac{34}{27} and y = \frac{73}{27}

Step-by-step explanation:

2x + 5y = 11

7x + 4y = 2

Let's try elimination here since we have a system of equations:

-7(2x + 5y = 11) = -14x - 35y = -77

and

2(7x + 4y = 2) = 14x + 8y = 4

The <em>x</em>'s cancel out now so let's combine the two equations:

-35 + 8 = -27

-77 + 4 = -73

-27y = -73

y = \frac{73}{27}

Now that we have <em>y</em>'s value, let's plug that value in for <em>y</em> in the other equation. You may choose whichever equation you want to solve for <em>x</em> but it is recommended to use the easiest one. (Since this value is complicated, it won't really matter.)

2x + 5(\frac{73}{27}) = 11

2x + \frac{365}{27} = 11

2x = -\frac{68}{27}

x = -\frac{34}{27}

To check and make sure you have the correct values, plug both values into the orginal equation and make sure the equation is true.

5 0
3 years ago
Read 2 more answers
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