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3 years ago

Solve b²-4b+4=0 using the quadratic formula PLEASE EXPLAIN HAS TEST ON FRIDAY!!

Mathematics

2 answers:

kolbaska11 [484]3 years ago

8 0

Answer:

b = 2

Step-by-step explanation by completing the square:

Solve for b over the real numbers:

b^2 - 4 b + 4 = 0

Write the left hand side as a square:

(b - 2)^2 = 0

Take the square root of both sides:

b - 2 = 0

Add 2 to both sides:

Answer: b = 2

pickupchik [31]3 years ago

4 0

I'm going to use x in place of b. The reason why is because 'b' shows up in the quadratic formula, so there might be some confusion.

So we want to solve x^2 - 4x + 4 = 0 for x

Note how this equation is the same as 1x^2 - 4x + 4 = 0 and it is in the format ax^2 + bx + c = 0

We see that a = 1, b = -4 and c = 4

We will plug these values into the discriminant formula

d = b^2 - 4ac

d = (-4)^2 - 4(1)(4)

d = 16 - 16

d = 0

The discriminant is 0, so the square root of this is also 0. A discriminant of 0 means that there is only one real solution.

It turns out that the solution is equal to x = -b/(2*a) = -(-4)/(2*1) = 4/2 = 2

If the discriminant were nonzero, then the quadratic formula would be a bit messier.

It might be better to factor. Doing so gets you (x-2)^2 = 0 which becomes x-2 = 0 and x = 2

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I have no idea how to solve this. <br> |x-3|=|5-x|

erica [24]

4-3=1 and 5-4= 1 so it's 4

3 0

3 years ago

Read 2 more answers

Plz help asap......................................

ziro4ka [17]

Option B:

Law of cosine, two sides and the included angle are known.

Solution:

Let us first know the law of cosines and law of sines.

Law of cosine:

If we know the sides a, b and the included angle θ, then we can find the third side c. This is known as the law of cosine.

$c^2=a^2+b^2-2abcos\theta$

Law of sine:

The sides of a triangle are to one another in the same ratio as the sines of their opposite angles.

$$\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}$

Given ∠P and the sides r, q are known.

<u>To find the value of p:</u>

Option A: Law of cosines, all sides are known.

It is false by the above definition of law of cosine.

Option B: Law of cosine, two sides and the included angle are known.

It is true by the above definition of law of cosine.

Option C: Law of sines, all sides are known.

It is false, because one angle is given in question.

Option D: Law of sines, two angles and the included side are known.

It is false, because two angles are not given.

Option B is the correct answer.

Hence the answer is "Law of cosine, two sides and the included angle are known".

7 0

3 years ago

F is the midpoint of EG If EF = x + 2 and FG = 2x - 6, find<br> FG

mezya [45]

Answer:

FG = 10

Step-by-step explanation:

EF = x + 2 ; FG = 2x - 6

F is the mid-point of EG. So, EF = FG

$= > x + 2 = 2x - 6$

$= > 2x - x = 6 + 2$

$= > x = 8$

FG = 2×8 - 6 = 10

8 0

3 years ago

WILL GIVE BRAINLIEST

scZoUnD [109]

Answer:

it is d

Step-by-step explanation:

6 0

2 years ago

**Giving away 20 points**. I need to know the arc length for EF and the area of sector EOF please:) (also plz show work thanks!!

LiRa [457]

Let us for a few seconds nevermind there's a circle at all, so we only really have a triangle by itself.

now, EF = 18, wait a second! EF is the base of the triangle, and h = 10.725, wait a minute!! "h" is the height of the triangle.

so, what's the area of a triangle whose base is 18 and has a height of 10.725? yeap, we knew you'd know that one.

what's the length of the arcEF? well, we know the central angle of ∡FOE is 80°, well, arc's get their angle measurement from the central angle they're in, so if ∡FOE is 80°, so is arcEF then.

3 0

3 years ago