Answer:
1,145,375 cm³
Step-by-step explanation:
Like with an earlier question you had, there is a chunk missing. If that chunk was filled in, this would be a 205 * 70 * 85 rectangular prism.
205 * 70 * 85
17,425 * 70
1,219,750
The cut out chunk is a 25 * 70 * 85 triangular prism.
1/2 (25 * 70 * 85)
1/2(2,125 * 70)
1/2(148,750)
74,375
Now that we know what the cut-out chunk is, subtract that from the first value we got.
1,219,750 -74,375
1,145,375 cm³
The volume of the Canadian Post mailbox is 1,145,375 cm³.
18.9 rounded is 19
5.2 rounded is 5
19 * 5 = 95
This is the correct answer to the problem
Answer:
6n²√3
Step-by-step explanation:
2√3n•√9n³
The above expression can be simplified as follow:
Recall
√9 = 3
2√3n•√9n³ = 2√3n × 3√n³
Recall
m√a × n√b = mn√(a × b)
Thus,
2√3n × 3√n³ = (2×3) √(3n × n³)
2√3n × 3√n³ = 6√3n⁴
Recall:
√aᵇ = (aᵇ)¹/² = aᵇ/²
√n⁴ = n⁴/²
√n⁴ = n²
Thus,
6√3n⁴ = 6n²√3
Therefore,
2√3n•√9n³ = 6n²√3
Answer:
Answer is c
Step-by-step explanation:
In hypothesis testing whether to accept or reject null hypothesis, normally we find one method as using confidence interval. If the test statistic lies within confidence interval, we accept otherwise we reject.
For arriving confidence intervals we add and subtract margin of error from the mean we use in null hypothesis.
Margin of error = std error * critical value of test (Z or t etc)
For the same std deviation, std error = std dev/sq rt of sample size
Thus std error is inversely proportional to the square root of sample size.
If n becomes larger, std error becomes smaller and vice versa.
So margin of error increases for smaller sample size.
Since we have to select confidence level from a small sample, we have to select one which has the greatest margin of error=18
Hence answer is
c) 71%(+/-18%)
