Answer:
F = 3x +(2.7×10^7)/x
Step-by-step explanation:
The formulas for area and perimeter of a rectangle can be used to find the desired function.
<h3>Area</h3>
The area of the rectangle will be the product of its dimensions:
A = LW
Using the given values, we have ...
13.5×10^6 = xy
Solving for y gives ...
y = (13.5×10^6)/x
<h3>Perimeter</h3>
The perimeter of the rectangle is the sum of the side lengths:
P = 2(L+W) = 2(x+y)
<h3>Fence length</h3>
The total amount of fence required is the perimeter plus one more section that is x feet long.
F = 2(x +y) +x = 3x +2y
Substituting for y, we have a function of x:
F = 3x +(2.7×10^7)/x
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<em>Additional comment</em>
The length of fence required is minimized for x=3000. The overall size of that fenced area is x=3000 ft by y=4500 ft. Each half is 3000 ft by 2250 ft. Half of the total 18000 ft of fence is used for each of the perpendicular directions: 3x=2y=9000 ft.
6 large + 5 small = 127 kg ------------ (1)
2 large + 3 small = 51kg ------------ (2)
<u>(2) x 3 :</u>
6 large + 9 small = 153 ---------------- (2a)
<u>(2a) - (1) :</u>
4 small = 26
1 small = 6.5kg ------------ (sub into equation 1)
6 large + 5 small = 127 kg
6 large + 5(6.5) = 127
6 large + 32.5 = 127
6 large = 127 - 32.5
6 large = 94.5
1 large = 15.75 kg
Answer: The small box weighs 6.5kg and the big box weighs 15.75 kg
Answer:
Step-by-step explanation:
using the distributive property, the answer is -6.
BC is the length of AD because they are parallel. Have a nice day
