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3 years ago

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Which congruence postulate is stated below If speak two angles and a non included side of one triangle are congruent to the corr

esponding two angles and side of another, then the triangles are congruent

1 answer:

Sveta_85 [38]3 years ago

6 0

Answer:

AAS

Step-by-step explanation:

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6. A super-bouncy-ball is thrown 25m into the air. The ball falls, rebounds to 70% of the height of the previous bounce and fall

inn [45]

Answer:

The total distance the ball has travelled after it hits the ground the 5th time is of 48.53m.

Step-by-step explanation:

Geometric sequence:

In a geometric sequence, the quotient of consecutive terms is the same. The nth term of a geometric sequence is given by:

$a_n = a_1q^{n-1}$

In which $a_1$ is the first term and $q$ is the common ratio.

A super-bouncy-ball is thrown 25m into the air. The ball falls, rebounds to 70% of the height of the previous bounce and falls again.

This means that:

$q = 0.7, a_1 = 25*0.7 = 17.5$

Then

$a_n = a_1q^{n-1}$

$a_n = 17.5(0.7)^{n-1}$

First 5 terms:

$a_1 = 17.5$

$a_2 = 17.5(0.7)^{2-1} = 12.25$

$a_3 = 17.5(0.7)^{3-1} = 8.58$

$a_4 = 17.5(0.7)^{4-1} = 6$

$a_5 = 17.5(0.7)^{5-1} = 4.2$

Find the total distance the ball has travelled after it hits the ground the 5th time.

$T = 17.5 + 12.25 + 8.58 + 6 + 4.2 = 48.53$

The total distance the ball has travelled after it hits the ground the 5th time is of 48.53m.

8 0

3 years ago

☆*☆=3x, if x is even and negative OR ☆*☆=4x, if x is odd. Following the rule above, what is the value of ☆ - 23 ☆?

Art [367]

Answer:

okay... Thanks have a great day!

7 0

3 years ago

Find the maximum and minumum of f(x) =<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D2%5Csqrt%7Bx%7D%20-3%5Csqrt%5B3%5D%7Bx%7D"

QveST [7]

Answer:

1/27 at (x.y)= (1/3, 1,3)

Step-by-step explanation:

Hope this helps:)

6 0

2 years ago

Area of rectangle with diagonal of 5 in but length not given

sergij07 [2.7K]

Draw a rectangle with diagonal 5 in. Inside this rect. are 2 acute triangles of hypotenuse 5. Note that 3^2 + 4^2 = 5^2; thus the width of the rect. is 3 and the length is 4, with the result that the hypo. is sqrt(3^2+4^2), as expected.

3 0

2 years ago

Find the area bounded by the graphs of the indicated equations over the given interval.

NeX [460]

Answer:

48

Step-by-step explanation:

$y = 0$

is basically the horizontal axis.

First, find the integral of x^2-25.

Remember that

integral of a constant is that constant times x.

Also that

to take the integral of a power function, add 1 to the degree and divide by that same degree.

$y = {x}^{2} - 25$

We then get

$\frac{ {x}^{3} }{3} - 25x$

Evaluate at -3

$\frac{ - 3 {}^{3} }{3} - 25( - 3)$

$- 27 + 75 = 48$

Then we evaluate at 0

$\frac{0 {}^{3} }{3} - 25(0) = 0$

Next, we subtract the the answer then we get

$48 - 0 = 48$

8 0

2 years ago