5. Y=1/2x+12
6. Y=4x+8
7. Y=1/4x+256
Part A: To get an equation into standard form to represent the total amount rented (y) that Marguerite has to pay for renting the truck for x amount of days, we use the formula for the equation of a straight line.
Remember that the equation of a straight line passing through points is ( x_{1} , y_{1} ) and the points ( x_{2} , y_{2} ) is given by
y - y_{1} / x - x_{1} = y - y_{2} / x - x_{2}
Knowing that Marguerite rented a truck at $125 for 2 days, we know if she rents the exact same truck for 5 days, she has to pay a total of $275 for the rent.
<span>
This means that the line modeling this situation crosses points at (2, 125) and (5, 275).
</span>
The equation modeling <span>the total rent (y) that Marguerite has to pay for renting the truck for x days is given by
</span><span>
y - 125 / x - 2 = 275 - 125 / 5 - 2 = 150 / 3 = 50
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But if you are writing the equation in standard form it would be <span>
</span><span>
50x - y = -25
Part B:
When writing the function using function notation it means you are making y the subject of the formula and then replacing the y with f(x).
</span>
If you remember that from part A, we have that the equation for the total rent which is y that Marguerite has to pay for renting the truck for x amount of days is given by
y = 50x + 25.<span>
</span><span>
Writing the equation using the function notation would give us this
f(x) = 50x + 25
Part C:
To graph the function, we name the x-axis the number of days and name the y-axis total rent. The x-axis is numbered using the intervals of 1 while the y-axis is numbered using the intervals of 50.
The points of </span>(2,125) and of (5,275) are marked on the coordinate axis and a straight line is drawn to pass through these two points.
Answer:
The distance between A and D to the nearest tenth is;
Explanation:
Given the two points;
Applying the distance between two points formula;
![d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
substituting the given coordinates we have;
![\begin{gathered} AD=\sqrt[]{(-3-6)^2+(-2-2)^2} \\ AD=\sqrt[]{(-9)^2+(-4)^2} \\ AD=\sqrt[]{81+16} \\ AD=\sqrt[]{97} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20AD%3D%5Csqrt%5B%5D%7B%28-3-6%29%5E2%2B%28-2-2%29%5E2%7D%20%5C%5C%20AD%3D%5Csqrt%5B%5D%7B%28-9%29%5E2%2B%28-4%29%5E2%7D%20%5C%5C%20AD%3D%5Csqrt%5B%5D%7B81%2B16%7D%20%5C%5C%20AD%3D%5Csqrt%5B%5D%7B97%7D%20%5Cend%7Bgathered%7D)
Simplifying;
Therefore, the distance between A and D to the nearest tenth is;
If you have to write the equation then it would be "5k + 6.7"
35 students would not know any of the three languages, because if 30 know French, 19 knew German, and 16 knew Russian, that must mean that 65 students know at least one of the three languages. So you subtract 65 from 100 and end up with 35
