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3 years ago

MULTIPLYING FRACTIONS YES IM AN IDOIT SO HELP ME PLEASE XOXOXOXOXOXOXOXOXOXOXOXXO

Mathematics

1 answer:

Allisa [31]3 years ago

3 0

2miles=20km
20km/4=5km
5km=0,5mile
Runned 0.5 miles in total

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V7x – 1 = 3<br> Please help this is algebra 2

kumpel [21]

Solving for X

7vx−1=3

7vx=3+1

7vx=4

vx=4/7

x=4/7/v

x=4/7v

Solving for Y

7vx−1=3

7vx=3+1

7vx=4

vx=4/7

v=4/7/x

v=4/7x

Hope this helps, HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)

- Cutiepatutie ☺❀❤

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2 years ago

True or false: an irrational number has infinite decimal places.

AleksAgata [21]

Answer:

True!

An irrational number has an infinite number of decimal places.

If the decimal ever ended, then the number would be rational.

Step-by-step explanation:

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3 years ago

Shinzou wo sasageyo

OLga [1]

Answer: ty

Step-by-step explanation:

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3 years ago

Read 2 more answers

Please answer this question<br><br> ONLY ANSWER IF YOU KNOW FOR SURE

Fittoniya [83]

The answer is 540 m2 hope this helps

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3 years ago

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"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen

Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± $Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ ]

Where

p' is the sample proportion/point estimator of the population proportion

$Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ is the margin of error (d) of the confidence interval.

$Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648$

$d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$

$d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }$

$(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}$

$n*(d*Z_{1-\alpha /2})^2= p'(1-p')$

$n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}$

$n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}$

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0

3 years ago