(a - 2b) • (2a - b) is how you factor this using FOIL
When we are given a line cutting diagonally from one corner of a rectangle to the opposite corner, we are given two triangles.
300ft
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| /|
| / |
| / |
| / |400ft
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| / |
|/ |
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*not to scale
Now, using the right-angle trigonometry rule, we can find the hypotenuse (the diagonal line) which represents the footpath.
a^2 + b^2 = c^2
{where a is one side length, b is another side length, and c is the hypotenuse}
Thus, we make c the subject of the equation and substitute the other known values:
c^2 = 400^2 + 300^2
= 160,000 + 90,000
= 250,000
Now we move the 'squared' (^2) from the left hand side to the right hand side. When moving it across the equal sign (=) the result becomes the 'root' of itself:
c = _/250,000
= 500
Therefore, the length of the diagonal path is 500ft.
the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
Answer:
you would need more info... do you have any more information for this question?
Step-by-step explanation: