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Elis [28]
4 years ago
6

scale drawing Gabriel planned a vegetable garden. Use the scale and the scale drawing to complete the following statements. The

length of the garden is meters. The width of the garden is meters. If the scale changes to 1 cm : 9 meters, the new length of the garden is meters and the new width of the garden is meters. The new length of the garden is times as long as the original length of the garden.
Mathematics
2 answers:
Alona [7]4 years ago
6 0

Answer:

The length of the garden is 21 meters.

The width of the garden is 5.25 meters.

If the scale changes to 1 cm : 9 meters, the new length of the garden is  63 meters and the new width of the garden is 15.75 meters.

The new length of the garden is 3 times as long as the original length of the garden.

Step-by-step explanation:

LuckyWell [14K]4 years ago
4 0

Length: 21 meters

Width: 5.25 meters

<u>Scale changes to 1 cm : 9 cm</u>

- Length: 63 meters

- Width: 15.75 meters

New length is 3 times old length

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We know that 1 pound equals 16 ounces. In this exercise we have 1/2 pounds, that is, half a pound or 0.5 pounds, therefore:

1/2 pound * 16 ounces / 1 pound = 8 ounces

Which means that he bought 8 ounces of grapes and not 5 how he had put it.

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Pavlova-9 [17]

The measure of the ∠Q = 41°

By law of cosines:

a law in trigonometry: the square of a side of a plane triangle equals the sum of the squares of the remaining sides minus twice the product of those sides and the cosine of the angle between them.

Which can we stated as:

{q}^2 = {p}^2 + {r}^2 - 2prcos(Q)\\{4}^2 = {6}^2 + {5}^2 - 2*6*5*cos(Q)\\\\

solving equation using normal algebra:

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Thus, Q = 41°

Hence, the measure of the smallest angle in a triangle whose sides have lengths 4, 5, and 6. ∠Q is 41°.

To learn more about Finding angles visit:

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A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

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