Question

One positive number is three more than twice another. If their product is 629, find the numbers.

Answer 1

Answer:

x = 17 and y = 37

Step-by-step explanation:

Let the numbers be x and y.

y = 3 + 2x

xy = 629

substituting y in the second equation we get

x(3+2x) = 629

3x + 2$x^{2}$ = 629

2$x^{2}$ + 3x - 629 = 0

Solving a quadratic equation by using its formula:

x = [-3 ±√(9-4(2)(-629)] / 4

x = [-3 ± √5041] / 4

x = [-3 ± 71] / 4

x = 17 and $\frac{-37}{2}$

Ignore the negative number in x and just use x = 17 in the first equation we get

y = 3 + 2(17) = 37