Well, if you want to get p by itself, you will have to multiply both sides by 5/2. 2/5 times 5/2 gives you 1p, or just p.
A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
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a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
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c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
I think the answer is 1.125 or 1.13
** hope this helps**
One half of 200 is 100 because 200 divided by 2 is 100
P.S: Please give me brainiest answer
Answer:
ab - b^2
Step-by-step explanation:
The area of the large rectangle is
A = a*b
The area of the unshaded region is
A = b*b
The area of the shaded region is the large rectangle minus the unshaded region
ab - b*b
or
ab - b^2
