From the sum of 4x² - 2x +6 and 2x² + 4x-1, subtract 5x2 + 2x -4.

Mathematics

2 answers:

stealth61 [152]2 years ago

4 0

Answer: $\large \boldsymbol {\sf x^2+9 }$

Step-by-step explanation:

$1) \\\\ \large \boldsymbol {} \sf 4x^2-2x+6 \\ + \\ \underline{2x^2+4x-1} \\\\6x^2+2x+5$ $2) \\\\ \large \boldsymbol {} \sf 6x^2+2x+5 \\-\\ \underline{5x^2+2x-4} \\\\x^2+9$

ikadub [295]2 years ago

3 0

Answer:

x² + 9

Step-by-step explanation:

4x² - 2x + 6 + 2x² + 4x - 1 = 6x² + 2x + 5

<u>Subtract:</u>

6x² + 2x + 5 - 5x² - 2x + 4 = x² + 9

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Answer:

The answer is 2.

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Step-by-step explanation:

Since your relation is a direct variation then the points on your line are of the form y=kx where k is the constant of variation (also called constant of proportionality)

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So all the points in this relation since it is a direct variation will be equal to y-coordinate/x-coordinate.

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