From the sum of 4x² - 2x +6 and 2x² + 4x-1, subtract 5x2 + 2x -4.

Mathematics

2 answers:

stealth61 [152]3 years ago

4 0

Answer: $\large \boldsymbol {\sf x^2+9 }$

Step-by-step explanation:

$1) \\\\ \large \boldsymbol {} \sf 4x^2-2x+6 \\ + \\ \underline{2x^2+4x-1} \\\\6x^2+2x+5$ $2) \\\\ \large \boldsymbol {} \sf 6x^2+2x+5 \\-\\ \underline{5x^2+2x-4} \\\\x^2+9$

ikadub [295]3 years ago

3 0

Answer:

x² + 9

Step-by-step explanation:

4x² - 2x + 6 + 2x² + 4x - 1 = 6x² + 2x + 5

<u>Subtract:</u>

6x² + 2x + 5 - 5x² - 2x + 4 = x² + 9

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Solve for u -16=8+4u simplify your answer as much as possible

satela [25.4K]

Answer:

U = -6

Step-by-step explanation:

-16 = 8 + 4u

-24 = 4u

-24/4 = 4u/4

-6 = u

6 0

2 years ago

HELP NEEDED I need some help here can anyone help please?

natima [27]

Answer:

It's nine plus negative three

6 0

3 years ago

Read 2 more answers

The sum of two polynomials is 10a^2b^2-8a^2b+6ab^2-4ab+2 if one addend is -5a^2b^2+12a^2b-5 what is the other addend

spayn [35]

Answer:

The other addend is $15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7$ .

Step-by-step explanation:

The other addend is determined by subtracting $-5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b-5$ from $10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a\cdot b^{2}-4\cdot a \cdot b + 2$ :