R = 11-2m
S = n+5
T = -m-3n+8
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Add up S and T to get...
S+T = (n+5)+(-m-3n+8)
S+T = n+5-m-3n+8
S+T = -m+(n-3n)+(5+8)
S+T = -m+(1n-3n)+(5+8)
S+T = -m+(-2n)+(13)
S+T = -m-2n+13
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Subtract that result from R
R - [S + T]
11-2m - [-m-2n+13]
11-2m +m+2n-13
(-2m+m) + (2n) + (11-13)
(-2m+1m) + (2n) + (11-13)
(-1m) + (2n) + (-2)
-m + 2n - 2
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The final answer is -m + 2n - 2
Answer:
1.53 would be the answer
Step-by-step explanation:
If you are rounding to the nearest hundredth you are rounding to the 2nd decimal place. Since the next number is under 5, we would just drop it.
An iterated integral is the outcome of taking integrals toward a function of more than one variable in such a way that part of the variables is treated as constants for each of the integrals.
From the given parameters, we are to write out five iterations for a triple integral;
where;
- the region is bounded by 0 ≤ z ≤ y, 0 ≤ y ≤ x², 0 ≤ x ≤ 8.
Thus, since x, y, z are functions of at least one variable, we can have the following iterations:
Learn more about iterated integrals here:
brainly.com/question/7009095
Answer:
5
Step-by-step explanation:
Answer:
The rate of change is "-3". Which means the rate at which the tractor uses fuel.
Step-by-step explanation:
The equation describes a line and any line follows the equation:
y = m*x + c
Where "m" is the rate of change and "c" is the shift on the line. Comparing the equation for the fuel and the equation from the line, the rate of change must be "-3". The rate of change in this context describes the speed at which the tractor uses fuel, at a rate of 3 gallons per hour.
